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Solving Differential  Equation of Motion 
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#1
Jan3013, 11:48 PM

P: 19

Let's say I have the equation:
##\ddot {\theta}(t)(J + y(t)^2) + 2 \dot {\theta}(t) y(t) \dot y(t) + \ddot y(t)Jn## It's the general form of an equation I'm working with to describe the motion of a beam. As you can see both ##{\theta}(t)## and y(t) are equations of t. J and Jn are just constants. I'm wanting to solve for ##{\theta}(t)##, ##\dot {\theta}(t)##, and ##\ddot {\theta}(t)## as a function of time. These will correspond to position, velocity, and acceleration around an axis. I'm not sure how to go about this (differential) generally, I'm wanting the solutions mentioned about to come out something like: ##{\theta}(t)## = (equation of t) Any help would be greatly appreciated! 


#2
Jan3113, 12:30 AM

P: 2,769

have you tried using e^iat style functions for theta(t)?
I ask because its sometimes used when you periodic motion which in your case is rotating about an axis. 


#3
Jan3113, 10:03 AM

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PF Gold
P: 39,300

That's not a differential equation. Is one of those "+" signs supposed to be an "=" sign? Or is the whole formula equal to something, say "0"?



#4
Jan3113, 10:07 AM

P: 19

Solving Differential  Equation of Motion
As for the other response, I thought of that, but I'm not sure the general solution to second order differential equations applies here. Both functions are dependent on "t". 


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