
#1
Feb213, 08:54 PM

P: 12

I recently asked myself the question "If all the stars in the universe condensed together to form a black hole how big would that black hole be?" Using the information from http://en.wikipedia.org/wiki/Observable_universe I got the approximate mass to be 3x10^52kg. After that it was just a matter of finding the Schwarzschild Radius. So...
2GM/c^2 = 2(6.67300x10^11)(3x10^52)/8.98755x10^16 = 4.45482918x10^25m Is this right? I feel like this number is too large since the overall size of the observable universe is ~4.3x10^26. It seems strange that the radius of this black hole would take up this much space since the universe is mostly empty already. Am I not taking something in to account? Am I just doing the math wrong? Or am I right and that's just how the universe is? 



#2
Feb213, 09:04 PM

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P: 5,720

I haven't looked at your math but a black hole made up of all the matter in the observable universe would be WAY smaller than the observable universe, not just a factor of 10. I would expect MANY orders of magnitude smaller.




#3
Feb213, 09:17 PM

P: 12

That's what I assumed too which is why I came here. Especially since I was only using the mass of stars!




#4
Feb313, 12:12 AM

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P: 11,057

Question about the universe and a black hole
The calculator at hyperphysics gives me the same number.
http://hyperphysics.phyastr.gsu.edu...ro/blkhol.html Wiki's article on Schwarzschild radius gives a radius of about 10 billion light years, which is 4.46x10^{25} meters. I just don't know what mass they used. http://en.wikipedia.org/wiki/Schwartzchild_radius 



#5
Feb313, 12:38 AM

P: 12





#6
Feb313, 02:43 AM

Astronomy
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I used an estimate of just the ordinary (baryonic) matter in the currently observable portion of the universe1.5 x 10^{53} kg.
Does that seem right to you? If I put this into google calculator 1.5e53 kg/(mass of sun) it tells me 7.5e22 This for the radius of the observable currently being about 46 billion LY. So the ordinary matter content of the observable is 7.5 x 10^{22} solar masses The bulk of that would be gas and dust, not stars. I think there are an estimated 10^{22} stars. So that 7.5 seems the right order of magnitude. The Schw. radius of a solar mass is 3 km. So let's put this into google calculator: "3*7.5e22 km in light years" It does the conversion and gives us 24 billion lightyears. That would be my backofenvelope rough estimate of the Schw. radius of all the ordinary matter in the observable. Drakkith found an estimate of around 10 billion lightyears. I suspect that is an orderofmagnitude estimate even rougher than mine. Very round numbers. The two are the same order of magnitude. The more massive a BH is, the lower "density" it has if you compare its mass with the conventional volume. because the mass goes up linearly with radius and the conventional sphere volume goes up as the cube of the radius. So it is not so surprising. I guess if you could carve out and isolate just the observable universe region, and stop its expansion, it would start to collapse. It is dense enough compared with a BH of the same general size. But of course it is not isolated as far as anyone knows. As far as we know the universe as a whole has no center and no boundary. And it is expanding very rapidly. So doesn't really have a chance of collapsing. Conditions just aren't right for collapse, even though on paper the density looks sufficient. 



#7
Feb313, 08:46 AM

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P: 1,129

This is just another way of looking at a wellknown idea which is related to the Dirac Large Numbers Hypothesis (LNH), to Mach's Principle and to ideas relating inertia to gravitational induction (usually known as the "Sum for inertia").
The result is known as the "WhitrowRandall Relation" (sometimes with other names such as "Sciama" included) and states that the sum of the potential terms (Gm/rc^{2}) for every mass in the universe gives a result of order 1. If you replace the sum with a total mass and an appropriately weighted "average" distance, this "average" distance is then of the same order as the Schwarzschild radius of the total mass of the universe. In General Relativity, if you accelerate local sources relative to a test mass, then this induces a tiny acceleration in the test mass in the same direction, requiring a tiny (unmeasurably small) opposing force to keep it at rest. The "Sum for inertia" idea says that perhaps you could extend this idea to considering what would happen if you consider a viewpoint where the whole universe is apparently accelerated relative to the test mass, in which case the induced force necessary to oppose that acceleration would be proportional to the mass of the test mass and the relative acceleration. This would effectively provide a neat explanation for inertia if the constant of proportionality for the whole universe happened to come out to exactly 1. Unfortunately, this cannot be the case in General Relativity, as exact equality requires G to vary slightly depending on the distribution of masses, with time and location, but experimental observations show that any variability of G with time or location seems to be too small to support this possibility. 



#8
Feb313, 09:43 AM

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P: 5,720

I'm surprised to see I was so far off on this. I've GOT to learn to stop trying to apply my own intuition to physics. I've HAVE already gotten over that in quantum mechanics.




#9
Feb413, 04:41 PM

P: 5





#10
Feb513, 06:06 PM

P: 5

Since this is my first (actual) post on this site, I will make it clear that I am not even close to being a math expert, fortunately Einstein was good at making very visual examples, and I was able to adapt quite a bit of his mathematics from rela tivity to variables I could relate to, also Einstein was very capable of explaining his ideas in either complex or simpler forms. The reason am writing about this is that I am an artist and poet, so my thoughts are made up of flowery words and images, not equations, But I have worked very hard to understand the General Theory of relativity, I won't use a lot of math in my \proofs" but instead use logic that leans toward philosophy. As far as your question is concerned, I am kind of on the fence when it comes to the big bang  vs  the big bounce theory, so there might be a possibility of this situation actually happening. Other than that I think the question is a bit extraneous, surely the theoretical mathematical model (or philosophically in my case) is a good activity to keep one's mind sharp, but the question has very little practical application. Looking through the \lenses" of General relativity, and using the concept of a singularity. the question you had is unresolvable (in the literal sense). If the universe has coalesced into one object, this factor would negate the terms \mass" and \size" because there would be no reference body to compare the black hole to, then it's mass would be irrelevant to the way the universe exists today. Because this singularity comprises the sum of all information, there would be no where for the object to go, so velocity wouldn't be a factor anymore, time would stop, because the gravitation would be infinate, unless gravitation ceased due no reference bodies available. in other words, without any other objects for comparison, the Black hole would not even exist by current standard On the other hand, we understand only a small portion of how black holes react within the event horizon,or do we understand exactly and dark matter/ en ergy is or what it does, other than create an apparent gravitational "field", which shouldn't happen because dark matter/ energy doesn't seem to have any mass, yet dark matter is probably the reason that galaxies formed and dark energy seems to cause expansion, but otherwise it can only be a wild guess as to what other function these forms of matter have. and that is something that needs to be factored in or out. I hope this made sense, it might not answer your question (especial due to my weakness in math) but I hope this answer will oer more questions. 


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