
#1
Feb913, 10:38 PM

P: 81

Hi,
Is is correct to say that the logarithm of base 2 of a number x, is the same thing as the square root of a number x? 



#2
Feb913, 10:50 PM

PF Gold
P: 5,705

Have you tried it on some values? Do you get the same results?




#3
Feb913, 10:50 PM

P: 784

No, not at all.
To say that ##\log_2{x} = y## you mean that ##x=2^y##, logarithms are just ways of 'inversing' exponentiation (roughly). To say that ##\sqrt{x}=y## you are saying that ##x = y^2##, completely different. However, there is a neat little tidbit that says that ##\sqrt{x}= e^\frac{\ln{x}}{2}## 



#4
Feb1013, 07:28 AM

P: 81

log base 2 is the same thing as square root?
Ok. But I can say that these 2 expressions are correct?
[itex]\log_{b} x = y[/itex], and [itex]b^y=x[/itex] 



#6
Feb1013, 12:33 PM

Mentor
P: 21,059




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