
#1
Feb1613, 08:48 AM

P: 266

So is the strength of gravity proportional to the speed of acceleration of gravity? So would an object with 2g of gravity have a 19.62 m/s^2 acceleration? Im sure this sounds like a stupid question




#2
Feb1613, 10:32 AM

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P: 5,682





#3
Feb1613, 11:01 AM

P: 554

Here's your belated award: And to answer the OP, when you say something "has X gravity", you're saying the same thing as "it produces a field of strength X", where X has units of acceleration. A "g" is such an unit, just as 1 m/s^2 is. Whichever you use doesn't matter. So, then, saying "it's got 2g of gravity" is exactly equivalent to saying "it's got 2*9,81m/s^2 of gravity" to "it's got a 2g gravitational field potential" to "it's got a 2*9,81m/s^2 gravitational field potential". If you put any kind of mass in such a field, it'll feel a force of gravity F=m*a, where a is the potential. It's improtant to remember, however, that whenever we talk about gravitational potential, we must specify a certain point in space in which we measure it. In most cases in everyday use it's obvious, but to be truly clear, one should say something like "it's got 2g on the surface", as the acceleration measured anywhere further from or closer to the centre of the field would be different. 



#4
Feb1613, 11:04 AM

P: 2,861

Strength of gravity question.
It's a badly worded question but...
If you are in space (eg a long way from a planet) in a rocket that is accelerating at 19.62 m/s^2 then it will feel like you are experiencing 2g. Your cup of coffee will feel twice as heavy (actually more so because your arm will also feel twice as heavy). 



#5
Feb1613, 11:14 AM

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#6
Feb1613, 11:19 AM

P: 266

Haha sorry. Isn't earth gravity acceleration something like 9.81 m/s^2? We also describe earths gravity as being 1g (I assume the g stands for gravity, if not, please tell me). So would an object with a gravity of 2g have an acceleration of 2*9.81 (19.62) or is the 9.81 a universal rate of acceleration? (Sorry meant to say rate, not speed of acceleration)




#7
Feb1613, 11:25 AM

Mentor
P: 40,878

If not, then ask again. (The phrase "an object with a gravity of 2g" is not clear.) 



#8
Feb1613, 11:31 AM

P: 266

Ahh i see. So theoretically, something falling towards the earth will have an acceleration slightly less than 9.81 (proportional to its distance from the surface) until the instant it hits the surface?




#9
Feb1613, 11:41 AM

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P: 40,878

But as long as you stay not too far from the earth's surface, you can consider the acceleration due to gravity to be a constant equal to g. 



#10
Feb1613, 12:19 PM

P: 45

F=G(m1*m2)/r^2 Where G is the gravitational constant, more or less that "universal rate" called a constant that you were asking about: G=6.67398 × 10^11 m^3 kg^1 s^2 m1 is the mass of the object (in kilograms) m2 is the mass of some other object (in kilograms) r is the distance between the centers of mass of the two objects (in meters) F is then the mutual force felt by each mass from the other mass (in Newtons) So m1 feels that force by m2 and m2 feels that force by m1, due to Newton's Third Law (equal and opposite reactions). Subsequently, the acceleration resulting from a single object (as opposed to the force on a second object), can be found by eliminating m2 from the equationyet it nevertheless still depends on a distance from the mass, namely r! a=G*m1/r^2 a is the acceleration (in m/s^2) This is a result of taking the force equation and using Newton's second law for a hypothetical second object F=m2*a: F=G(m1*m2)/r^2=m2*a > a = G*m1/r^2 Edit: So, using the mass and radius of the Earth we have: a = G*m1/r^2 = (6.67398 × 10^11 m^3 kg^1 s^2)*(5.972 × 10^24 kg)/(6.373 × 10^6 m)^2 = 9.81 m/s^2 The actual acceleration depends on a person's specific location on the surface of the Earth. It can vary from around 9.78 m/s^2 to 9.83 m/s^2 on Earth's surface, and possibly more at the extremes, depending on latitude and height above/below sea level, among other things. 



#12
Feb1813, 03:27 AM

P: 768

On the moon, you would accelerate at 1.62 m/s^2. Nothing universal about 9.81 m/s^2. It's just something we happen deal with every day. 


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