
#1
Feb1913, 11:04 PM

P: 26

Find the solution y = φ(t) of the given problem and evaluate φ(t) at t = 0.1, 0.2, 0.3,
and 0.4. 1.y'=3+ty y = φ(t)=t2e^t y(1)= 0+(02e^0)*(.1)=.8 and the correct answer is 1.19516 2. y'=2y1 What I'm getting stuck on is do I use the formula y(n)=y(n1)+f(t(n1),y(n1)h because when I do I do not get the same answers as back of the book. Thanks for the help! 



#2
Feb2013, 08:01 AM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,881

(And, again, you cannot solve a first order differential equation for a specific value with an "initial condition". What are you using for t_{0} and y_{0}? 



#3
Feb2013, 08:03 AM

P: 26

y(0)=1/2



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