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gravity? and light? |
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| Aug31-03, 07:55 AM | #1 |
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gravity? and light?
hey im only a year 11 student and just wanna solve a arguement with my brother i pride myself on bing quite a head of my class in physics and such.. but the problem is that i belive that light behaves with gravity as it has mass even though to travel at the spped of light it cant have mass such as things like light distorts as it passes a sunn or it gets sucked into a balckhole couldnt happen if light didnt behave as if it had mass.... r there any sites that i can show to my borther to prove this or any one with a qualification in a field they can say deffiently this happens?
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| Aug31-03, 09:51 AM | #2 |
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When you used the term "mass" above where the say that the mass of a photon is zero, what you were really doing is saying that light has zero rest mass. In what follows I will use the term "mass" to refer to "relativistic mass." Since light has both energy and momentum it has mass but it does have zero "rest mass." I don't care for the term "rest mass" since a photon can never be at rest so you really can't measure it to me zero. I prefer the term "proper mass" which also is used to refer to "rest mass" In Einstein's 1916 review paper "The Foundation of the General Theory of Relativity" Einstein wrote http://www.geocities.com/physics_world/grav_light.htm In fact Einstein stated something similar tow hat you're thinking about. In his book "The Evolution of Physics." Commenting on the observation made by an observer inside an accelerating elevator that light is ‘weightless’ he writes (page 221) http://www.astro.washington.edu/tmur...s/AB05.05.html Also try searching under the phrase "mass density of radiation." You'll find that there are two answers to your question though. And they are exact opposites. But keep in mind that when someone says the light *does not* have mass, then they are refering to "rest mass." And if they say that light is not attracted by massive bodies, that they are moving through curved space then keep in mind that this is not quite an accurate statement - General relativity is based on the notion that gravitational mass and inertial mass are proportional to each other. And from Einstein's E = mc^2 he was led to equations which demand that light is deflected and moves throught curved spacetime *because* it has mass. If an object had no mass then it would not be effected by curved spacetime - since there are no objects that have no mass then we don't have to worry about that. So all things have energy and thus all things have mass and thus all things are deflected by gravity. Pete |
| Aug31-03, 11:14 AM | #3 |
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But really it is necessary to give the other side. If light has mass, how much mass does it have? If you naively multiply its zero "rest mass" by the infinite Lorentz factor associated with c, you get an undefined quantity. And if you examine the actuality of the bending of light in GR, you conclude that what is "attracted" in light is not mass, but energy.
So modern physicists are careful to avoid the term "rest mass" and use instead the term "invariant mass". And going along with this they attribute the Lorentz change to the energy, not the mass, so the invariant mass really is invariant, not changed by Lorentz transformations. And the bending in GR is attributed to this important fact. Energy gravitates. Indeed the mathematical expression for the real world "stuff" that bends spacetime is called the momentum-energy-stress tensor, and it has components of all those things, momentum, and energy, and stress (or change in momentum-energy). They all "gravitate", and a light beam, with no mass at all, can bend spacetime with its energy. |
| Aug31-03, 11:29 AM | #4 |
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gravity? and light?
Allow me to clarify some issues: These days, when a particle physicist says something is massive or massless, they are referring to what would formerly be known as "rest mass". This is because, decades ago, people used to talk of "relativistic mass". Unfortunately, this terminology has continued on in non-technical literature, and even basic physics texts.
Mass in quantum field theory (the basis of our understanding about what particles are) is a "good quantum number", being an eigenvalue of the "mass-squared" operator, which commutes with the Hamiltonian operator (the generator of time translations). All of this tells us that the mass of a particular species of particle, like an electron, is a well defined notion, even if the electron speeds up, slows down, or interacts with other particles (as long as there is no interaction where the electron is no longer in the system, e.g., in interacting with a positron to form two photons). As long as the electron is present, we know what we mean by the "mass of the electron". As for massless vs. massive particles: the fact that a particle can be massless (like a photon) is *intimately* connected with the fact that we can't go to a rest frame of the particle...in fact, a particle is massless when we can't go to its rest frame and vice versa. Therefore, via special relativity, it is quite necessary to have a notion of "massless" (using the correct definition of mass in quantum field theory that we did above). Now, Einstein's field equations state that anything with energy gravitates. Well, photons and electrons always have some energy (even though photons are massless, they have energy E=h(frequency)). Therefore, both photons (which in large numbers can make up a ray of light) and electrons (and all matter for that matter) will be affected by a gravitational field. In turn, anything with energy is a source of gravitational field; that is, in general relativity, energy and momentum in a region of space determine the geometry of spacetime around it, which then tell objects like photons and electrons how to move. |
| Aug31-03, 03:52 PM | #5 |
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m = m_o/sqrt[1-(v/c)^2] is derived on the assumption that the particle can be at rest and therefore is not a photon. To derive the mass relation for light you can do what Einstein did and derive it on the basis that the center of mass of a system is conserved. You then get m = E/c^2 for the mass of the photon. In this derivation no assumption is made regarding the photon other than it has energy and momentum. http://www.geocities.com/physics_wor...***_tensor.htm http://www.pma.caltech.edu/Courses/p...p23/0223.1.pdf http://www.pma.caltech.edu/Courses/p...p24/0224.1.pdf I can't find the term "invariant mass" in this text. But I do find the term "rest mass" all over the place When you say that "energy is the source, not mass" all you're doing is arguing semantics and what word to use in a sentance. They are equivalent - so it makes no difference. Pmb |
| Aug31-03, 03:59 PM | #6 |
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As I said above it's best to call this proper mass rather than rest mass - IMHO Pmb |
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