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1D wave PDE with extended periodic IC

by eckiller
Tags: extended, periodic, wave
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eckiller
#1
Oct6-05, 11:21 AM
P: 45
I have formula for 1D wave equation:

(*) u(x, t) = 1/2 [ f(x + ct) + f(x - ct) ] + 1 / (2c) Integral( g(s), wrt
s, from x-ct to x+ct )

I am trying to find u(1/2, 3/2) when L = 1, c = 1, f(x) = 0, g(x) = x(1 -
x).

However, for (*) to work, the initial position f(x) and initial velocity
g(x) must be extended to periodic functions.

"To determine f(x) and g(x) we need only find the integer n s.t. nL <= x <
(n+1)L, [where L is the right boundary length from the origin]."

It then gives the ways of extending if n is even or odd. If even, gx) =
g(x - nL). If odd, g(x) = -g((n+1)L - x).

How do I determine what n is for g to extend it correctly?

I need to figure out nL <= x < (n+1)L, yes. But what is x for g? For
f(x+ct) it is clear. But g is in the integral...
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stunner5000pt
#2
Oct6-05, 06:48 PM
P: 1,440
did you take your question from 'A First Course in Partial Differential Equations with complex variables and transform methods' by H F Weinberger?

anyway here is that question i had posted earlier
http://physicsforums.com/showthread.php?t=90027


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