# Calculus

by gillgill
Tags: calculus
 P: 128 1. Assume that total revenue from the sale of x television sets is given by R(x)=1000(1-(x/5))^2 a)find the marginal revenue when 400, 500, 600 sets are sold i found that R'(x)=-4 +(x/125) is it correct? therefore R'(400)=$-0.8 R'(500)=$0 R'(600)=\$0.8 ?? b)find the average revenue form the sales of x sets ave R(x)=R(x)/x would it equal (1000/x)(1-(x/500))^2 ?? could it be simplify further? c) Find the marginal average revenue. ave R'(x)=R'(x)/x =(-4/x)+(1/125) am i correct on all of these?? 2. The cost is dollars of manufacturing x items is given by C=2000x+3500 demand equation is x=√(15000-1.5p) in terms of the demand x, a) find an expression for the revenue R does that mean R(x)=px R(x)=p√(15000-1.5p) or u solve for p instead?
P: 307
 1. Assume that total revenue from the sale of x television sets is given by R(x)=1000(1-(x/5))^2 a)find the marginal revenue when 400, 500, 600 sets are sold i found that R'(x)=-4 +(x/125) is it correct?
Nope, applying the chain rule you get (-1/5)*(2)*1000(1-(x/5)) which, upon simplification yields R'(x)=-400+80x
Kevin
 P: 128 o..my mistake...the question is actually R(x)=1000(1-(x/500))^2 then is my answer right now?
P: 307

## Calculus

yep, at least as far as R'(x) is concerned, I don't know any economics so I won't say anything else about the rest of the problem.

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