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| Nov12-05, 11:06 PM | #1 |
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help me
how to calculate the number of prime factors of 360? please give the method
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| Nov13-05, 01:46 AM | #2 |
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Recognitions:
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HINT: Factor the number. :)
P.S. And, no, I am not being glib! |
| Nov13-05, 07:22 AM | #3 |
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As Tide said: start factoring. It's not that hard. I'll get you started:
360= 2(180)= 2(2)(90)= ... surely you can do the rest yourself. Did you mean number of distinct prime factors or just number of prime factors (i.e. counting "2" more than once). |
| Nov13-05, 10:38 PM | #4 |
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help me
I am sorry my question was wrong .however I wanted to ask how to find the no: of perfect squares in 360 without factorizing. I am sorry for sending the wrong question.
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| Nov14-05, 12:39 AM | #5 |
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That's a different question; prime factorization of 360 yields
[tex] 360 = 2^3 3^2 5 [/tex] and therefore the only perfect-square factors included are [tex] {\{1,4,9,36\}} [/tex] from observing the prime factorization. There are only four perfect-square factors of 360. (The "1" is trivial tho )*Then again, I'll reply later when I'll write an explicitly mathematical way to calculate the quantity of perfect-square factors of 360-->without factorization, as you mentioned
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