## frobenius method

for the frobenius method, why do you suppose that a0=1?
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 Recognitions: Gold Member Science Advisor Staff Emeritus You don't. You assume that it is non-zero which is just a choice of "c". The idea of Frobenius method is to write a solution in the form $$\Sigma_{n=0}{\infnty}a_n x^{n+c}$$ where c, while a constant, is not necessarily a positive integer. If I, choosing c to be, say, c[sub]0[/sup], I find that a0= 0 but a1 is not, I could just take c= c0+ 1 instead.
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