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Finding the kernel and range of a tranformation

 
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Dec1-05, 10:17 AM   #1
 

Finding the kernel and range of a tranformation


If L(x) = (x1, x2, 0)^t and L(x) = (x1, x1, x1)^t

What is the kernel and range?
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Dec1-05, 06:16 PM   #2
 
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Quote by Noone1982
If L(x) = (x1, x2, 0)^t and L(x) = (x1, x1, x1)^t
What is the kernel and range?
You have defined two different functions. Which one are you referring to?

Do you know the DEFINITION of "kernel"
Dec1-05, 07:15 PM   #3
 
I need to do both. I know the kernel is basically setting to zero, but my book is awful on explaining stuff. I also know the range is basically solving for y and row reducing, but I am foggy on the presentation.
Dec1-05, 09:11 PM   #4
 
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Finding the kernel and range of a tranformation


I'll explain it to you, and I want to see you attempt to answer it.

The range is simple. It's just like Calculus, sort of.

For example, the function f(x)=x^2 has a domain of R(-infinite,infinite), and range (0,infinite).

The range is simply all the possible vectors you can obtain from the transformation. If T(x) = (0,0), then all the possible vectors that come "out" of the transformation are in the set {(0,0)}, which is the range.

What's the range of T(x)=(x,y)?

The answer is R^2, which is any vector in the Cartesian Plane.

The kernel of a transformation is the set of vectors that transform into the zero vector. So, for the first one T(x)=(0,0) is all the vectors, since all the them become a zero vector, so the answer is R^2.

What's the kernel of T(x)=(x,y)?

Well, the only possible vector that can transform into a zero vector is the zero vector itself.

Note: I have no idea what you mean by exponent t. Maybe that signifies that it is a transformation... I have no idea.
Dec2-05, 06:20 AM   #5
 
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Quote by Noone1982
I need to do both. I know the kernel is basically setting to zero, but my book is awful on explaining stuff. I also know the range is basically solving for y and row reducing, but I am foggy on the presentation.
Your book is awful on explaining "setting to zero"?? Not a whole lot to explain is there?

For your first function L(x1,x2,x3))= (x1, x2,0).
Set that equal to 0: (x1, x2,0)= (0, 0, 0).

What does that tell you about x1 and x2? What does it tell you about x3?

Now the range: what do all possible values of L, that is all vectors of the form (x1, x2,0), have in common?
Dec2-05, 06:56 AM   #6
 
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Quote by JasonRox
Note: I have no idea what you mean by exponent t.
It means transpose. For example (5,2,3) is a row matrix (i.e., a 1x3 matrix) and (5,2,3)^t is a column matrix (i.e., a 3x1 matrix).

Regards,
George
Dec2-05, 09:04 AM   #7
 
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Quote by George Jones
It means transpose. For example (5,2,3) is a row matrix (i.e., a 1x3 matrix) and (5,2,3)^t is a column matrix (i.e., a 3x1 matrix).
Regards,
George
I know what transpose means.
Dec2-05, 09:51 AM   #8
 
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Then I'm surprised that you don't know that AT is a standard notation for transpose.
Dec2-05, 12:22 PM   #9
 
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Quote by HallsofIvy
Then I'm surprised that you don't know that AT is a standard notation for transpose.
Exactly... capital T.
Dec2-05, 01:01 PM   #10
 
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You can't guess that lower and upper case t in an expression x^t or x^T where x is a vector don't both obviously mean transpose?
Dec2-05, 03:23 PM   #11
 
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Quote by matt grime
You can't guess that lower and upper case t in an expression x^t or x^T where x is a vector don't both obviously mean transpose?
I didn't think the transpose was necessary.

Anyways, the question isn't about transposes.
Dec2-05, 03:29 PM   #12
 
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It's about vectors, and linear maps. What on Earth was it going to be except transpose?
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