Register to reply

Recursive question

by flying2000
Tags: recursive
Share this thread:
Dec3-05, 12:55 PM
P: 40

T(0) = 1
T(n) = T(n-1) + root(T(n-1))

how many recursion does T(n) need to grow to the number k?
can I get this? root(k) < m < c root(k)
c is constant and m is the times we need for T(n) goes to k.

Any help appreciated!!
Phys.Org News Partner Mathematics news on
Heat distributions help researchers to understand curved space
Professor quantifies how 'one thing leads to another'
Team announces construction of a formal computer-verified proof of the Kepler conjecture
Dec3-05, 10:18 PM
Sci Advisor
P: 2,751
You can bound it with a continous function.

Try solving dy/dx = sqrt(y) with y(0)=1, you can show that this function is bigger than T but gives a pretty good bound. Solving the above gives c=2 as the constant you're looking for.

BTW: Maybe I'm just dumb but I had to read you post about three times before I figured out that by "root" you meant square root or sqrt or [tex]\sqrt(.)[/tex].

Register to reply

Related Discussions
Recursive Relations. Set Theory, Logic, Probability, Statistics 0
Recursive definition Calculus & Beyond Homework 3
Recursive algorithm Calculus & Beyond Homework 6
Recursive question Calculus & Beyond Homework 1
Non-recursive formula General Math 3