# compatibility of qunatum measurements

by sachi
Tags: compatibility, measurements, qunatum
 P: 76 The question is "two operators A,B do not commute". Is it true that ([A,B]psi) does not equal zero for any state psi?" I'm not sure if there are any cases in which a state psi could produce this result (except for the obvious one where psi = 0 and there is no particle). Thanks
 Sci Advisor HW Helper P: 1,320 Here is a hint: think about the commutator $$[x^2 , p]$$. Can you find a state that gives zero when you hit it with the commutator even though commutator isn't identically zero?
 P: 76 I've tried applying the commutator to an arbitrary psi and i get i*h bar * 2x* psi. The only case where I can think of this equalling zero is when psi = 0, which is the obvious case of having no particle.