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Multiple integrals |
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| Dec21-05, 09:13 PM | #1 |
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Multiple integrals
Hi, I posted a question some time ago and the suggestion was to use some form of the product rule but I still can't figure out what to do.
Q. Let f(x,y,z) and g(x,y,z) be C^2 scalar functions. Let D be an elementary region in space and [tex]\partial D[/tex] be the closed surface that bounds D. Prove that [tex]\int\limits_{}^{} {\int\limits_{}^{} {\int\limits_D^{} {\nabla f \bullet \nabla g} dV = \int\limits_{}^{} {\int\limits_{\partial D}^{} {f\nabla g \bullet dS} - \int\limits_{}^{} {\int\limits_{}^{} {\int\limits_D^{} {f\nabla ^2 gdV} } } } } } [/tex] Can someone give me a hint as to where to start, like any relevant identies which could be of use? Any help is appreciated thanks. |
| Dec21-05, 09:59 PM | #2 |
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Recognitions:
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The following identity should help:
[tex]\nabla \cdot (f \vec A) = \vec A \cdot \nabla f + f \nabla \cdot \vec A[/tex] Which is just one of the 3D versions of the product rule. (You can substitute [itex] \nabla g[/itex] into this formula) |
| Dec21-05, 10:00 PM | #3 |
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Thanks for the help, I'll try to finish this one off.
Edit: Hmm...I could've sworn that your post made mention of the divergence theorem before...nevermind, I'll keep that in mind.;) |
| Dec22-05, 09:18 AM | #4 |
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Recognitions:
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Multiple integrals
Yea, sorry about that. I had originally told you how to do the problem step by step, but I realized that's not what this forum is for, so I changed it. But yes, the divergence theorem is necessary.
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| Dec22-05, 08:18 PM | #5 |
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Oh ok, it doesn't really matter too much now. The divergence theorem is the only connection I know of between surface and volume integrals so I probably would've used it eventually anyway.
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