Frequency, Period, Displacement of Springs: Solving Problems

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Homework Help Overview

The discussion revolves around a particle's motion described by a displacement function involving cosine, focusing on determining frequency, period, maximum displacement, and velocity at specific times.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationships between displacement and velocity, with some attempting to apply calculus to find the derivative for velocity. Questions arise regarding the correctness of initial answers and the need for clarification on the derivative process.

Discussion Status

The conversation includes attempts to derive velocity from displacement, with some participants confirming understanding of the derivative process. There is ongoing clarification regarding the correct application of calculus, but no consensus on the final velocity value has been reached.

Contextual Notes

Participants express uncertainty about their calculations and the relationships between the variables involved, indicating a need for further exploration of the concepts without providing definitive answers.

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A particle has displacement given by[tex]x=3.0\cos(5\pi t+\pi)[/tex] where x is in meters and t in seconds

A)What are the frequency ,F, and the period,T, of motion
B)What is the greatest distance the particle travels from equlibrium
c)Where is the particle at time t=0?t=0.5(s)
D)What is the velocity when t=0.5s

A)F=2.5, T=0.4
B)3.0M
c)3.0M
d)no idea

thank you
 
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Apply the formula for velocity i.e dy/dx
 
I have no idea what you are talking about? are my other answers correct?
 
d)no idea

Others are correct i thought you need to calculate the velocity
dont u
 
yes i need to calculuate velocity, but i don't know how to get it.
 
Look you got the displacement, Pls tell yourself what is the relation between displacement and velocity
 
ok so i have to take the derivative

[tex]x=3.0\cos(5\pi t+\pi)[/tex]

so the derivative of that would be

[tex]3.0*-\sin(5\pi(0.5)+\pi)*d/dx(5\pi(0.5)+\pi[/tex]
 
Yes You got it right
 
yes but i get v=0 when i do the derivative. is this correct?

thnx for ur help
 
  • #10
Sorry U didn't write correctly
[tex]3.0*-\sin(5\pi(0.5)+\pi)*d/dx(5\pi(0.5)+\pi[/tex]

it should be
[tex]3.0*-\sin(5\pi(0.5)+\pi)*d/dt(5\pi(0.5)t+\pi[/tex]

I want to correct myself
Apply the formula for velocity i.e dy/dx

the velocity is time derivative
i.e v = dx/dt.

i just wanted to point towards the calculus involved
 
  • #11
thnx a lot man
 

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