- #1
jybe
- 41
- 1
Homework Statement
A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 6.30 N is applied. A 0.540-kg particle rests on a frictionless horizontal surface and is attached to the free end of the spring. The particle is displaced from the origin to x = 5.00 cm and released from rest at t = 0. (Assume that the direction of the initial displacement is positive. Use the exact values you enter to make later calculations.)
1) Determine the displacement x of the particle from the equilibrium position at t = 0.500 s.
2) Determine the velocity and acceleration of the particle when t = 0.500 s.
Homework Equations
[/B]
x = Acos(2pi*f*t)
v = -Aωsin(2pi*f*t)
a = -Aω^2cos(2pi*f*t)
Already found ω = 19.72 rad/s
frequency = 3.139 s^-1
The Attempt at a Solution
1)
x = 0.05*cos(pi*3.139)
x = 0.04926 m or 4.926 cm
2)
v = -0.05*19.72*sin(pi*3.139)
v = -0.168869 m/s
a = -0.05*(19.72)^2*cos(pi*3.139)
a = -19.1566 m/s^2
My answers for angular velocity and frequency are correct but apparently my answers for position, velocity and acceleration are wrong. Do I need my calculator in radians?