Equality holds in Minkowski's Inequality whenby benorin Tags: equality, holds, inequality, minkowski 

#1
Jan1106, 07:19 AM

HW Helper
P: 1,007

I would like to determine necessary and sufficient conditions for equality to hold in Minkowski's Inequality in [itex]L^{p}(X,\mu)[/itex].
For [itex]1\leq p\leq \infty,[/itex] we have [itex]\forall f,g\in L^{p}(X,\mu)[/itex] [tex]\left\{\int_X \left f+g\right ^{p} d\mu\right\} ^{\frac{1}{p}} \leq \left\{\int_X \left f\right ^{p} d\mu\right\} ^{\frac{1}{p}} + \left\{\int_X \left g\right ^{p} d\mu\right\} ^{\frac{1}{p}}[/tex] here I wish to allow f and g to be complex. Any help would be nice. 



#2
Jan1206, 06:20 AM

HW Helper
P: 1,007

So I think I have all the pieces, but I lack your brain power.
Minkowski's Inequality is proved (in Rudin's text) via Holder's Inequality, namely For [itex]\frac{1}{p}+\frac{1}{q}=1[/itex], [itex]1< p< \infty,1<q< \infty,[/itex], and let f and g be measurable functions on X with range in [itex]\left[ 0, \infty\right] [/itex]. Then [tex]\left\{\int_X fg d\mu\right\}\leq \left\{\int_X f^{p} d\mu\right\} ^{\frac{1}{p}}\left\{\int_X g^{q} d\mu\right\} ^{\frac{1}{q}}[/tex] To prove Minkowski's put [itex](f+g)^{p}=f(f+g)^{p1}+g(f+g)^{p1}[/itex] and apply Holder's inequality to each of the terms on the right, that is [tex]\left\{\int_X f(f+g)^{p1} d\mu\right\}\leq \left\{\int_X f^{p} d\mu\right\} ^{\frac{1}{p}}\left\{\int_X (f+g)^{(p1)q} d\mu\right\} ^{\frac{1}{q}}[/tex] and [tex]\left\{\int_X g(f+g)^{p1} d\mu\right\}\leq \left\{\int_X g^{p} d\mu\right\} ^{\frac{1}{p}}\left\{\int_X (f+g)^{(p1)q} d\mu\right\} ^{\frac{1}{q}}[/tex] note that (p1)q=p and that 1/q=11/p then add the above inequalities to get Minkowski's inequality in the following form: [tex]\left\{\int_X \left( f+g\right) ^{p} d\mu\right\} ^{\frac{1}{p}} \leq \left\{\int_X f^{p} d\mu\right\} ^{\frac{1}{p}} + \left\{\int_X g^{p} d\mu\right\} ^{\frac{1}{p}}[/tex] for nonnegative f and g. Equality holds in Holder's inequality if, and only if, there are constants a and b such that [itex]af^p=bg^q[/itex]. To arrive at the form of Minkowski's inequality I have posted above, note that [tex]\left f + g \right \leq \left f \right + \left g \right \Rightarrow \left f + g \right ^{p} \leq \left( \left f \right + \left g \right \right) ^{p}[/tex] by the triangle inequality. For complex f and g, their magnitudes f and g are nonnegative and measurable if f and g are (so it is ok to generalize as such.) Based on the conditions for equality to hold in Holder's Inequality, what are the conditions for equality to hold in Minkowski's Ineqaulity for complex f and g? 



#3
Jan1206, 09:17 AM

P: 943

when one function is a constant multiple of the other, ie f = ag or somethng like that



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