Register to reply

Is more work required for this spring?

by endeavor
Tags: required, spring, work
Share this thread:
Jan11-06, 10:20 PM
P: 176
A spring with a force constant of 50 N/m is stretched continuously from x0=0 to x2=20 cm. Is more work required to stretch the spring from x1=10 cm to x2=20 cm than from x0 to x1? Justify your answer mathematically.

I thought the work required is the same because the displacements are equal for both work equations... but I think I'm wrong.
Phys.Org News Partner Science news on
Wildfires and other burns play bigger role in climate change, professor finds
SR Labs research to expose BadUSB next week in Vegas
New study advances 'DNA revolution,' tells butterflies' evolutionary history
Jan11-06, 10:25 PM
P: 223
work = 1/2 kx^2

so then the difference would be greater between 20cm and 10cm

w= EPEf-EPEi = 0.5(k)400-0.5(k)100 = 150k
w0->1 = 0.5(k)(100) - 0.5k(0) = 50k
Jan11-06, 10:27 PM
P: 176
but wouldn't it be:
work1 = 1/2 k (10cm)^2
work2 = 1/2 k (20cm - 10cm)^2=work1

Jan11-06, 10:57 PM
P: 223
Is more work required for this spring?

no, the work is the difference between energies.

[tex] EPE_i + W = EPE_f [/tex]
[tex] W = EPE_f - EPE_i [/tex]
[tex] W = 0.5kx_f^2 - 0.5kx_i^2 [/tex]
Jan11-06, 11:08 PM
P: 176
I remember now...

what does EPE mean?
Jan11-06, 11:18 PM
P: 24
elastic potential energy

Register to reply

Related Discussions
What is the energy/work required to turn something? General Physics 47
Work required to stack books Introductory Physics Homework 14
How much work is required? Introductory Physics Homework 2
Calculation work required from change in pH Biology, Chemistry & Other Homework 0
Work Required to Submerge Introductory Physics Homework 3