- #1
Need help with electric field calculation? Check out part B!
- Thread starter Lewis
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- Electric Electric field Field
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Homework Help Overview
The discussion revolves around calculating the electric field in a specific scenario, particularly focusing on part B of a problem related to charge distributions. The original poster expresses difficulty in starting the problem and references an attachment for context.
Discussion Character
- Exploratory, Assumption checking
Approaches and Questions Raised
- Participants discuss the challenges of accessing the problem details due to attachment issues and suggest alternative ways to share the information. There is a mention of using the electric field of a ring to approach part B, along with integration techniques for calculating the electric field from a disk of charge.
Discussion Status
Some participants have provided insights into potential methods for solving part B, including specific formulas and integration strategies. The conversation indicates a collaborative effort to clarify the problem and explore different approaches, though no consensus or final solution has been reached.
Contextual Notes
Participants note the difficulty in accessing the original problem due to it being presented as an image, which may limit the discussion's progress. There is also an acknowledgment of the original poster's uncertainty regarding their previous answer for part A.
- #2
Meir Achuz
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I can't open your attachment. Why don't you cut and paste and put it in without the attachment?Lewis said:I'm having trouble with the question included in the attachment, part B specifically. If anyone could start me off it would be a great help!
Also, my answer for part A is included if anyone would care to check it
-Note: Chances are it's wrong
- #3
Lewis
I can't copy and paste cause it's a picture, however perhaps the following will work for you:
http://www.geocities.com/shinra_clan1/Physics1.JPG
Thanks a bunch!
http://www.geocities.com/shinra_clan1/Physics1.JPG
Thanks a bunch!
- #4
Meir Achuz
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I also get your answer to (A), with \lambda=Q/h.
I think the easiest way to do (B) is:
1. Use the field of a ring to get the field a distance z from a disk of charge Q. Use dq=2pi r dr/(pi r^2 Q) and integrate r from 0 to R.
This should give E=(2Q/R^2)[1-z/sqrt{z^2+R^2}].
2. Integrate E for the disk the same way you must have done for E for the ring for the hollow cylinder.
Let me know if you want to know the answer.
I think the easiest way to do (B) is:
1. Use the field of a ring to get the field a distance z from a disk of charge Q. Use dq=2pi r dr/(pi r^2 Q) and integrate r from 0 to R.
This should give E=(2Q/R^2)[1-z/sqrt{z^2+R^2}].
2. Integrate E for the disk the same way you must have done for E for the ring for the hollow cylinder.
Let me know if you want to know the answer.
- #5
Lewis
Cool, I got it now.
Thanks man, and sorry for the slow reply.
Thanks man, and sorry for the slow reply.
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