## Basic solution help

Hi I am studying for this first physics test and having trouble.

heres the eqation im using to find x and im sure its right but i can't seem to get the answer they do

x=8.0m/s*5.0s +.5 * 3.0m/s^2 * (5.0s)^2 = 77.5

I am not getting the 77.5

8 *5 = 40

3.0 x 5.0 = 15

15 * .5 = 7.5

so 40 + 7.5 = 47.5

I have a feeling that it has something to do with the time being squared buy my algebra sucks.. can someone explain this solution.

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 the equation is $$x=\frac{1}{2}at^2+v_ot$$ you forgot to square the time when multiplying against acceleration
 What is the question? what is the problem with things you have done? Pls be specific.

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## Basic solution help

 Quote by mrserv0n Hi I am studying for this first physics test and having trouble. heres the eqation im using to find x and im sure its right but i can't seem to get the answer they do x=8.0m/s*5.0s +.5 * 3.0m/s^2 * (5.0s)^2 = 77.5 I am not getting the 77.5 8 *5 = 40 3.0 x 5.0 = 15 15 * .5 = 7.5 so 40 + 7.5 = 47.5 I have a feeling that it has something to do with the time being squared buy my algebra sucks.. can someone explain this solution.
x=8.0m/s*5.0s +.5 * 3.0m/s^2 * (5.0s)^2 = 77.5

Yes, it is "the time being squared"- you didn't square! What is 52?