How does the orbital diameter of 2003 UB313 compare to its orbital period?

In summary, the newly discovered object 2003 UB313 has a very elongated orbit that takes it up to 97 times farther from the Sun than Earth, making it almost twice as far as Pluto. However, its orbital period is only 2.25 times longer than that of Pluto, with an estimated time of about 558 years. This is determined using Kepler's law, which states that the period is proportional to the square root of the semi-major axis of the orbit. Therefore, there is a direct correlation between orbital diameter and orbital period, but it is not logarithmic as previously thought.
  • #1
DaveC426913
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Is this true?

(excerpted from http://www.astro.uni-bonn.de/~bertoldi/ub313/" about 2003 UB313)

"...Its very elongated orbit takes it up to 97 times farther from the Sun than is the Earth - almost twice as far as the most distant point of Pluto's orbit – so that it takes twice as long as Pluto to go around the Sun..."

Is there a direct correlation between orbital diameter and orbital period? I would have thought it would be logarthmic.
 
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  • #2
DaveC426913 said:
Is this true?

(excerpted from http://www.astro.uni-bonn.de/~bertoldi/ub313/" about 2003 UB313)

"...Its very elongated orbit takes it up to 97 times farther from the Sun than is the Earth - almost twice as far as the most distant point of Pluto's orbit – so that it takes twice as long as Pluto to go around the Sun..."

Is there a direct correlation between orbital diameter and orbital period? .

Yes there is...
but they've made very rough verbal approximations.
Actually to make orbital period determinations you must use the semi-major axis of the orbit.
In this case the semi- major axis of UB313 is 67.7 AU compared to Pluto's 39.5 AU. So it is really only 1.7 times as distant as Pluto.

The orbital period vs. orbital radius (s-m axis) scales as T^2/R^3, (Kepler's law).

So the period T = sq.rt.(1.7)^3 = 2.25, meaning its orbital period is 2.25 times that of Pluto.
Since Pluto's orbital period is 248 yrs, then the orbital period of UB313 is about 558 yrs. -- Approximately since all my figures are truncated.

Creator:biggrin:
 
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What is the relationship between orbital period and diameter?

The orbital period and diameter of a celestial object are directly related to each other. The larger the diameter of an object, the longer its orbital period will be. This is because the gravitational force between two objects is directly proportional to their masses and inversely proportional to the square of the distance between them. Therefore, objects with larger diameters have greater mass and require a longer orbital period to maintain their orbit.

How does the orbital period affect the diameter of a celestial object?

The orbital period of a celestial object is determined by its distance from the body it is orbiting and its mass. As the orbital period increases, the diameter of the object can also increase. This is seen in the case of gas giants such as Jupiter, which have longer orbital periods and larger diameters compared to rocky planets like Earth.

What factors can affect the orbital period and diameter of a celestial object?

Several factors can influence the orbital period and diameter of a celestial object. These include the mass and distance of the object it is orbiting, the presence of other nearby objects, and any external forces acting upon it, such as gravitational pull from other bodies in the solar system.

Is there a direct correlation between the orbital period and diameter of a celestial object?

While there is a general relationship between orbital period and diameter, it is not a direct correlation. Other factors, such as the eccentricity of an orbit and the gravitational pull of other objects, can also impact the orbital period and diameter of a celestial object.

How do scientists use the orbital period and diameter of a celestial object to study its properties?

By studying the orbital period and diameter of a celestial object, scientists can gather information about its mass, composition, and distance from other objects. This helps in understanding the formation and evolution of the object, as well as its relationship with other objects in the solar system.

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