What are the first and second derivatives of the function

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Homework Help Overview

The discussion revolves around finding the first and second derivatives of the function f(x)=(3-x)/(2x+5). Participants are exploring the application of differentiation rules, particularly the quotient rule and the product rule.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster questions whether to use the quotient rule or to rewrite the function for the product rule. Some participants express preferences for one method over the other, while others discuss the correctness of derivative calculations.

Discussion Status

There are differing opinions on the correctness of the derivative calculations provided by one participant. Some participants are questioning the accuracy of the derivatives and discussing potential mistakes, while others reference external resources for verification.

Contextual Notes

Participants are considering the implications of using different differentiation methods and the potential for errors in derivative calculations. There is also mention of a desire for additional resources to analyze the function further.

roy5995
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What are the first and second derivatives of the function

f(x)=(3-x)/(2x+5)

How do i find them, do i use the quotient rule or do i change it to

f(x)=(3-x)*(2x+5)^-1 and use the product rule?
 
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Personally I like the product rule better, but you get the same answer either way, so use whichever one you prefer.
 
I think i got it

f'(x)= -11(2x+5)^-2
f''(x)= 44(2x+5)^-3

but does anyone know of a website where i can type in the function and it will show me all the max, mins, asymptotes, holes, cusps ...
 
You made a mistake when you combined your terms in the first deriv., & therefore the 2nd is wrong too.
 
How are roy's answers incorrect?

f'(x)= -11(2x+5)^-2
f''(x)= 44(2x+5)^-3

-11 times the quantity (2x+5) to the power of -2 is the correct answer as seen http://home.twmi.rr.com/faust9/calc problem.jpg

roy's answer could be written:

f'(x)= -11/(2x+5)^2
f''(x)= 44/(2x+5)^3

and it would be equivalent to what he has above.
 
Last edited by a moderator:
Sorry those are not incorrect
 

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