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potential energy question |
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| Mar12-06, 11:56 AM | #1 |
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potential energy question
An infinite sheet of charge that has a surface charge density of 21 nC/m2 lies in the yz plane, passes through the origin and is at a potential of 1.3 kV.
A long wire having a linear charge density of 50 nC/m lies parallel to the y axis and intersects the x axis at 3.2m. The permittivity of a vacuum is 8.85419*10^-12 C2/N.m2 What is the potential energy of a 2.4 nC charge placed at x = 1.5 m in units of J. can anybody help me.. I dont know how to use the 1.3 kV potential I used V=(入/ 2Eoл)× Ln(r1/r2) , U=V×q but I entered the answer, it was wrong
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| Mar12-06, 02:16 PM | #2 |
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Recognitions:
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If the infinite sheet has a uniform charge density, and there are other charges present, it can’t be an equipotential. |
| Mar12-06, 02:40 PM | #3 |
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never mind~ I got the right answer~!!!! ^^: finally
Vb-Va=-21n×1.5/2Eo -> Vb=1300-1779.661= -479.661 VB-VA(0)=50n/ (2лEo) × Ln(3.2/1.7) = 568.7519 3.2-1.5=1.7 U=q(Vb+VB) = 2.4n × (568.7519-479.661)=2.13818×10^-7 |
| Mar13-06, 05:32 AM | #4 |
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Recognitions:
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potential energy question
But that answer is wrong because of my first post.
If there is a charged wire and a point charge present, the plane cannot be at a constant potential of 1.3 kV. Is it stated that that is the potential at the origin or on the whole plane? Also, watch your sig. figs. |
| Mar13-06, 11:06 PM | #5 |
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well, actually I'm still confused but I entered the answer and it was right >,< I didn't skip any words... what I put on the first post is exactly I have on my paper
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