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Incorrect Wikipedia Article? |
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| Mar12-06, 10:46 PM | #1 |
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Incorrect Wikipedia Article?
Hey folks,
I'm currently studying sequences and the like in Calc 2, and I went to Wikipedia for another explaination about them. The example given in the article located here seems to be incorrect to me. The example is this: [latex]\sum _{n=0}^{\infty }{2}^{-n} = 2[/latex] I was thinking it's equal to zero though, since when n is really large, then the bottom gets really big so the whole fraction would head to zero. Am I wrong or is the author wrong? |
| Mar12-06, 10:57 PM | #2 |
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This is a series, and not a sequence.
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| Mar12-06, 11:04 PM | #3 |
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Yeah, that's what I meant to say
... but should that change the answer?
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| Mar12-06, 11:11 PM | #4 |
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Incorrect Wikipedia Article?
Well, yes. A "series", a "sum of a series", a "sequence", and a "limit of a sequence" are all very different things.
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| Mar12-06, 11:19 PM | #5 |
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You're thinking of [itex]\lim_{n \to \infty} 2^{-n}[/itex], which is zero. However [itex]\sum 2^{-n} = 1 + \frac{1}{2} + \frac{1}{4} + \cdots[/itex] isn't zero.
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| Mar12-06, 11:47 PM | #6 |
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Yes, that answer is correct. [tex]1 + \frac{1}{2} + \frac{1}{4} + \cdots[/tex] does indeed equal 2.
I probably solve simple series like this in a unique way, but I tend to imagine it in the number base 2 (binary). This would essentially be 1.11111111 repeating. This is like our 9.9999 repeating = 10, only that in binary is 2. |
| Mar13-06, 07:07 AM | #7 |
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Recognitions:
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![]() This is a geometric series with the first term 1, and the common ratio r = 1 / 2. So apply the formula to find the sum of the first n terms of a geometric series, we have: [tex]S_n = a_1 \frac{1 - r ^ n}{1 - r}[/tex] Now r = 1 / 2. So |r| < 1, that means: [tex]\lim_{n \rightarrow \infty} r ^ n = 0[/tex] Now let n increase without bound to get the sum: [tex]\sum_{n = 0} ^ {\infty} 2 ^ {-n} = \lim_{n \rightarrow \infty} S_n = \lim_{n \rightarrow \infty} a_1 \frac{1 - r ^ n}{1 - r} = \frac{a_1}{1 - r} = \frac{1}{1 - \frac{1}{2}} = 2[/tex]. Can you get this? :) ------------- @ KingNothing: Have you leant geometric series? We don't need to complicate the problem in binary, though. Just my $0.02. |
| Mar13-06, 11:52 PM | #8 |
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Doh!! I get it now! Thanks folks... and I apologize for my confusion :(... it's all a little complicated when you first learn it.
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