Finding Perpendicular Vectors with Sum [6,8]

Click For Summary

Homework Help Overview

The discussion revolves around finding two vectors, u and v, that are perpendicular, with one vector having twice the magnitude of the other, and their sum equaling [6, 8]. The problem is situated within the context of vector mathematics.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore relationships between the magnitudes and components of the vectors, questioning how to express |v|^2 in terms of the components a, b, c, and d. There is also discussion about deriving equations from the conditions given, such as the dot product being zero for perpendicularity and the sum of the vectors.

Discussion Status

The discussion is ongoing, with various participants attempting to derive equations that relate the components of the vectors. Some guidance has been offered regarding the need for multiple equations to solve for all variables involved, and there is an acknowledgment of the relationships between the magnitudes of the vectors.

Contextual Notes

Participants note the challenge of deriving sufficient equations from the given conditions, with an emphasis on the need for four equations to solve for the four unknowns (a, b, c, d). There is also a mention of the importance of correctly applying the relationships between the magnitudes of the vectors.

PiRsq
Messages
112
Reaction score
0
Find 2 vectors u and v such that they are perpendicular one of the vector is twice the magnitude of the other. And the sum vector of u and v is [6,8]

I did:

Let u=[a,b]
Let v=[c,d]
Let |u|=2|v

u.v=ac+bd=0

|u+v|=|u|^2 + |v|^2

But |u|=2|v|

|u+v|=5|v|^2

5|v|^2=100

|v|^2=20

Im stuck after this
 
Physics news on Phys.org
You forgot to write ^2 on |u+v|

Anyways, can you write |v|^2 in terms of a, b, c, and d? Do you know what |u|^2 is? Have you used the fact that u + v = [6, 8] yet?
 
So

|u|^2+|v|^2=|u+v|^2

But since |u|^2=4|v|^2

5|v|^2=36+64
|v|^2=20

now where can I go?
 
Can you write |v|^2 in terms of a, b, c, and d? Do you know what |u|^2 is? Have you used the fact that u + v = [6, 8] yet?
 
|v|^2 = c^2+d^2

|v|^2 = 1/2 (a^2 + b^2)


1/2(a^2+ b^2)= c^2 + d^2

Is that what you mean?
 
Can you think of anything better you can do with those first two equatinos?
 
Since |v|^2=2|u|^2,

|v|^2 = c^2+d^2

|u|^2 = 1/2 (c^2 + d^2)


|u|^2 + |v|^2 = 100

3/2 (c^2 + d^2) = 100

I don't know where I am headed
 
what formulas do you have involving |v|^2?
 
Projection of u on v

u on v = [u.v/|v|^2] |v|
 
  • #10
I guess I should have asked this first off...

You know that your goal is to find 4 equations involving only a, b, c, d which you can solve, right?
 
  • #11
4 equations?? I didnt know that...I've been focusing on finding a and b
 
  • #12
Well, you have 4 unknowns; a, b, c, and d. In general, you need 4 equations to solve for all 4 of them.

Sometimes you can get lucky and you can find two equations that involve only a and b, but in general that won't happen (and I'm pretty sure it doesn't here)...


You've already found one good equation:

ac + bd = 0


You just need 3 more! You can get 2 more equations out of what you've told me about |v|^2...


Oh, BTW, if |u| = 2|v|, then |u|^2 = 4|v|^2
 
  • #13
Ill try this and post a little later, thanks man
 

Similar threads

Replies
23
Views
2K
  • · Replies 2 ·
Replies
2
Views
911
  • · Replies 1 ·
Replies
1
Views
975
  • · Replies 15 ·
Replies
15
Views
1K
Replies
12
Views
2K
Replies
13
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
4
Views
2K
Replies
5
Views
1K