# Euler's Method question.

by que
Tags: euler, method
 P: 3 I need some clarification please the question is: -Using Euler's method with h = .25 given dy/dx = ycosx ,y(0) = 1 on the interval 0 <= x =< pi/4. are the X's : pi/12, pi/6, pi/4 OR .25, .50, .75 ?? some help please que.
 Mentor P: 7,203 $$x_0=0$$ $$x_1 = x_0 +h$$ $$x_3 = x_0 + 2*h$$ Continue until $$x_n > \frac { \pi } 4$$
 PF Patron Sci Advisor Thanks Emeritus P: 38,395 Start at 0 and go by steps of h: 0, .25, .50, .75, 1, 1.25, 1.50. It's a bit peculiar to use an h that does not divide evenly into the length of the interval. Are you sure you have read the problem correctly?
P: 3

## Euler's Method question.

ok so what i get.
(x0,y0) = (0,1)
X1 = .25
Y1 = 1 + .25(1*cos(0)) = 1.25
i do this until x3,y3 where x3 = .75, and y3 = 1.8935
do i stop there since doing one more step will be > pi/4?

thanx.
 P: 3 yes HallsofIvy i read the problem correctly that why i was confused since all the book problems use an h that is divide evenly into the length of the intervals.

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