
#1
Mar2406, 05:27 PM

P: 3

I need some clarification please the question is:
Using Euler's method with h = .25 given dy/dx = ycosx ,y(0) = 1 on the interval 0 <= x =< pi/4. are the X's : pi/12, pi/6, pi/4 OR .25, .50, .75 ?? some help please que. 



#2
Mar2506, 01:42 AM

Mentor
P: 7,291

[tex] x_0=0 [/tex]
[tex] x_1 = x_0 +h [/tex] [tex] x_3 = x_0 + 2*h [/tex] Continue until [tex] x_n > \frac { \pi } 4 [/tex] 



#3
Mar2506, 06:01 AM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,879

Start at 0 and go by steps of h:
0, .25, .50, .75, 1, 1.25, 1.50. It's a bit peculiar to use an h that does not divide evenly into the length of the interval. Are you sure you have read the problem correctly? 



#4
Mar2606, 12:04 AM

P: 3

Euler's Method question.
ok so what i get.
(x0,y0) = (0,1) X1 = .25 Y1 = 1 + .25(1*cos(0)) = 1.25 i do this until x3,y3 where x3 = .75, and y3 = 1.8935 do i stop there since doing one more step will be > pi/4? thanx. 



#5
Mar2606, 12:07 AM

P: 3

yes HallsofIvy i read the problem correctly that why i was confused since all the book problems use an h that is divide evenly into the length of the intervals.



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