Euler's Method question.


by que
Tags: euler, method
que
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#1
Mar24-06, 05:27 PM
P: 3
I need some clarification please the question is:
-Using Euler's method with h = .25 given dy/dx = ycosx ,y(0) = 1 on the interval 0 <= x =< pi/4.

are the X's : pi/12, pi/6, pi/4 OR .25, .50, .75 ??

some help please

que.
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Integral
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#2
Mar25-06, 01:42 AM
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[tex] x_0=0 [/tex]
[tex] x_1 = x_0 +h [/tex]
[tex] x_3 = x_0 + 2*h [/tex]

Continue until

[tex] x_n > \frac { \pi } 4 [/tex]
HallsofIvy
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#3
Mar25-06, 06:01 AM
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Start at 0 and go by steps of h:
0, .25, .50, .75, 1, 1.25, 1.50.

It's a bit peculiar to use an h that does not divide evenly into the length of the interval. Are you sure you have read the problem correctly?

que
que is offline
#4
Mar26-06, 12:04 AM
P: 3

Euler's Method question.


ok so what i get.
(x0,y0) = (0,1)
X1 = .25
Y1 = 1 + .25(1*cos(0)) = 1.25
i do this until x3,y3 where x3 = .75, and y3 = 1.8935
do i stop there since doing one more step will be > pi/4?

thanx.
que
que is offline
#5
Mar26-06, 12:07 AM
P: 3
yes HallsofIvy i read the problem correctly that why i was confused since all the book problems use an h that is divide evenly into the length of the intervals.


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