
#1
Apr1506, 01:24 AM

PF Gold
P: 7,125

The question is:
[tex] \[ \begin{array}{l} E_n = n^2 \frac{{\pi ^2 (\hbar c)^2 }}{{2mc^2 L^2 }} \\ L = 2*10^3 nm \\ m = 5.11*10^5 eV \\ \hbar c = 197.33eV*nm \\ \end{array} \][/tex] Using this, I find n=1 to equal 9.40*10^8 eV The book says im good there. The problem is when I have to find the second energy level. I figured you use n=2 which means its just 2^2 or 4 times the energy but the book says its just 2 times the energy of the first energy level. What am I not understanding here? 



#2
Apr2010, 08:17 PM

P: 1

I'm pretty sure the book made a mistake. For n=2, E2 = 4*E1 = 3.8 X 10^7. I double checked with cramster, and that's how it was done there also.



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