Can you assume that Jupiter has a circular orbit?

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SUMMARY

The discussion centers on the assumption of Jupiter's orbit being circular and the implications for spacecraft trajectories. It highlights that spacecraft traveling to outer planets can achieve speeds 1.5 times that of Jupiter, resulting in hyperbolic orbits around the Sun. The Vis-Viva equation is crucial for calculating orbital velocities, with the gravitational parameter (μ) for Earth being 398600.4 km³/sec². The eccentricity of planetary orbits is typically very small, allowing for the approximation that the distance (r) is nearly equal to the semi-major axis (a).

PREREQUISITES
  • Understanding of the Vis-Viva equation for orbital mechanics
  • Knowledge of gravitational parameters in celestial mechanics
  • Familiarity with the concepts of eccentricity and semi-major axis in orbits
  • Basic principles of hyperbolic and parabolic trajectories
NEXT STEPS
  • Study the application of the Vis-Viva equation in various orbital scenarios
  • Research the gravitational parameter (μ) for different celestial bodies
  • Explore the characteristics of hyperbolic and parabolic orbits
  • Learn about the calculations for escape velocity in orbital mechanics
USEFUL FOR

Astronomers, astrophysicists, aerospace engineers, and students studying orbital mechanics will benefit from this discussion.

yxgao
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When it is about the same distance from Jupiter, spacecraft on a mission to the outer planets has a speed that is 1.5 times the speed of Jupiter in its orbit. Why does the orbit of the spacecraft about the sun follow a hyperbolic orbit?

Can you assume that Jupiter has a circular orbit? So far I've tried caltulating the total energies of the spacecraft and of Jupiter but I don't think that's correct.
 
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Use the Vis-Viva equation

[tex] <br /> V=\sqrt{\frac{2}{r}-\frac{1}{a}}<br /> [/tex]

It's a safe assumption (unless they give it to you explicitly) that the eccentricity of planetary orbits are very small. That means that r~=a.

What is the semimajor axis of a parabolic (or hyperbolic) orbit? You can solve for escape velocity with that.
 
I made a mistake.

Vis Viva is:

[tex] <br /> V=\sqrt{\mu*(\frac{2}{r}-\frac{1}{a})}<br /> [/tex]

Where mu is the gravitational parameter, G*M or 398600.4 km^3/sec^2
 

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