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Surface w/ max volume and min surface area |
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| May16-06, 05:38 PM | #1 |
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Surface w/ max volume and min surface area
I'm attempting to solving this problem but do not know how to begin. Any help would be appreciate.
What geometric surface encloses the maximum volume with the minimum surface area? How would you prove it? |
| May17-06, 03:07 AM | #2 |
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Well, first of all, you should state your question more precisely:
Alternative 1: Of all geometric objects with the same volume, which has minimal surface area? Alternative 2: Of all geometric objects with the same surface area, which encloses the maximal volume? Under certain assumptions of niceness, you may solve problems like these with the calculus of variations. Yhen, in both cases, the ball (solid sphere) will be your solution. |
| May17-06, 03:26 AM | #3 |
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If you have some constraints, use Lagrange multipliers.
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| May17-06, 07:54 AM | #4 |
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Surface w/ max volume and min surface area |
| May17-06, 08:02 AM | #5 |
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Since there is only one answer to this question (i.e., a sphere) is there a proof for this? Intuitively it makes sense that it would be a sphere, but there must be a rigorous way to demonstrate this..
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| May17-06, 08:07 AM | #6 |
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I'm out of touch with it, but I'm pretty sure you can use the Calculus of Variations to do it.
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| May17-06, 09:59 AM | #7 |
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Isn't this related to the (very hard) Plateau problem?
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| May17-06, 02:16 PM | #8 |
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Yes, the general study of functions giving maximal values (as opposed to numbers) is precisely the "Calculus of Variations". And, yes, one can prove, using the calculus of variations, that, under certain conditions, the surface enclosing maximum volume for given surface area, or, conversely, having minimum surface area for given volume, is a sphere.
There do, however, exist rather peculiar 'special surfaces' that also have those properties. |
| May17-06, 07:13 PM | #9 |
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Well, I have a feeling that the answer would be a sphere but I just don't know how to solve it using calculus. Any hint would help alot.
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| May17-06, 07:58 PM | #10 |
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| May18-06, 07:41 AM | #11 |
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Typically, those surfaces that cannot be discerned by standard variational techniques, yet represent extremizing values, are non-smooth surfaces.
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| May18-06, 11:35 AM | #12 |
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| Jul7-06, 08:15 PM | #13 |
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hi guys
would it possible for somebody to actually write out the mathematical calculations for the calculation of miminum surface area of a bubble using the Euler-Lagrange Differential Equation. thanks vishak |
| Jul7-06, 10:27 PM | #14 |
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