- #1
cphill29
- 16
- 1
The problem is, find the surface area of the volume of revolution generated by rotating the curve y=e2x between x=0 and x=2 about the x-axis.
Here's what I have so far...
SA=∫y√(1+y2)dx
=∫e2x√(1+4e4x)dx
and from here I'm not really sure what to do. Any help would be appreciated.
Here's what I have so far...
SA=∫y√(1+y2)dx
=∫e2x√(1+4e4x)dx
and from here I'm not really sure what to do. Any help would be appreciated.