How to Verify the Energy of a Scattered Photon Formula?

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Homework Help Overview

The discussion revolves around verifying the energy of a scattered photon in a collision involving an electron and a gamma ray photon, framed within the context of Compton scattering and relativistic Doppler effects.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the relativistic Doppler equation and the Compton scattering formula to derive the energy of the scattered photon. There are attempts to reconcile different forms of the equations and clarify the transformations involved.

Discussion Status

Some participants are seeking guidance on applying the relevant formulas correctly, while others express confusion regarding the manipulation of terms within the equations. There is an ongoing exploration of the mathematical relationships without a clear consensus on the resolution of the issues raised.

Contextual Notes

Participants note the complexity of the problem and the challenges faced in understanding the transitions between different forms of the equations, particularly in the context of the observer's motion relative to the source.

Reshma
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An electron of mass 'm' and speed 'v' collides with a gamma ray photon of initial energy hf0, as measured from the laboratory frame. The photon is scattered in the electron's direction of travel. Verify that the energy of the scattered photon, as measured in the laboratory frame, is:
[tex]E = hf_0\left(1 + \frac{2hf_0}{mc^2}\sqrt{\frac{1 + v/c}{1 - v/c}}\right)^{-1}[/tex]

Well this also seems to be a Compton effect problem. The relativistic Doppler equation for frequency is given by:
[tex]f = f_0\sqrt{\frac{1 - \beta}{1 + \beta}}[/tex]
where [itex]\beta = v/c[/itex]

Need guidance to apply this formula to obtain above result...
 
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Reshma said:
An electron of mass 'm' and speed 'v' collides with a gamma ray photon of initial energy hf0, as measured from the laboratory frame. The photon is scattered in the electron's direction of travel. Verify that the energy of the scattered photon, as measured in the laboratory frame, is:
[tex]E = hf_0\left(1 + \frac{2hf_0}{mc^2}\sqrt{\frac{1 + v/c}{1 - v/c}}\right)^{-1}[/tex]

Well this also seems to be a Compton effect problem. The relativistic Doppler equation for frequency is given by:
[tex]f = f_0\sqrt{\frac{1 - \beta}{1 + \beta}}[/tex]
where [itex]\beta = v/c[/itex]

Need guidance to apply this formula to obtain above result...
Use the Compton formuala to determine the energy of the photon after the collision in the frame of the electron before the collision. Then apply the Doppler equation to get the energy in the lab frame.

AM
 
Last edited:
Thank you for the hints here on how to solve it but I have been working on this problem for several days now and I keep getting to similar places after using the compton scattering and doppler effect but I can't see how sqrt((1-v/c)/1+v/c)) is becoming sqrt((1+v/c)/(1-v/c))
can someone please explain this?
 
BlazzedTroll said:
Thank you for the hints here on how to solve it but I have been working on this problem for several days now and I keep getting to similar places after using the compton scattering and doppler effect but I can't see how sqrt((1-v/c)/1+v/c)) is becoming sqrt((1+v/c)/(1-v/c))
can someone please explain this?
v is negative if the observer is moving away from the source and positive if the observer is moving toward the source.

AM
 

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