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Destructive Interference in Thin Film Interference |
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| May30-06, 04:22 AM | #1 |
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Destructive Interference in Thin Film Interference
Two oblong pieces of plane glass are separated from each other by a thin sheet of cellophane and held together with rubber bands, as shown in figure(I provided a website for the figure below), where the amount of separation is much exaggerated. If you place a "sodium vapor lam" vertically above the glass plates, you will observe an alternate series of very close bright and dark lines. A light wave is reflected at point A and simply forms a returning wave. Some of the original light wave crosses the narrow air gap and is reflected at point B. If it advances across the air gap as a trough, then it is reflected at point B as a crest.
Question: The length of the wedge-shaped space between the two glasses is l, the thickness of the thin sheet of cellophane is d, and the distance between point C and point A (or B) is x as shown in the figure.Supposing the result is destructive interference or darkness. Find the relation between x, [tex]\lambda[/tex],l and d. My idea: I think their relation is x=[tex]\frac{l}{2d} \lambda(n + \frac{1}{2}) [/tex] This is the website: www.geocities.com/willydavidjr/interference.html |
| May31-06, 01:15 AM | #2 |
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Recognitions:
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At A the ray is reflected from rarer medium (air) and at B it is reflected from denser medium (glass). When a wave is reflected from a denser medium an additional path difference of (lembda/2) is to be considered. Did you considered this additional path difference?
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