Register to reply

Change in acceleration due to gravity

by shill
Tags: acceleration, gravity
Share this thread:
Jun13-06, 03:34 PM
P: 5
I'm a grade 11 student (I haven't formally learned calculus yet, but I've been dabbling with online tutorials) with a question (not for homework, just something I've been thinking about). For relatively small distances from Earth, we can estimate that the acceleration of a falling object will be constant (9.8 m/sē). However, that is obviously not the case once you start getting farther away. How can we describe the motion of an object falling to Earth from very far away? Does it have a constant jerk (change in acceleration), or does that also change?

This is related to a question I read on this forum (
Phys.Org News Partner Science news on
'Office life' of bacteria may be their weak spot
Lunar explorers will walk at higher speeds than thought
Philips introduces BlueTouch, PulseRelief control for pain relief
Jun13-06, 03:42 PM
Sci Advisor
PF Gold
Hootenanny's Avatar
P: 9,772
What is the equation for gravitational field stregth? (AKA acceleration due to gravity)
Jun13-06, 11:09 PM
P: 5
Quote Quote by Hootenanny
What is the equation for gravitational field stregth? (AKA acceleration due to gravity)
g = G*m/rē
where G is a constant, and m is a constant for a given body (at least in classical physics). So acceleration is proportional to 1/rē.

But wait... that still doesn't describe the object's motion with respect to time. If I have an object, (for example, with a mass of 1 kg, and a distance of 600 km), how can I figure out what the acceleration will be a second from then if I know the initial acceleration?

Jun14-06, 06:20 AM
P: 1,235
Change in acceleration due to gravity

Your are right:

that still doesn't describe the object's motion with respect to time
But, g = Gm/r² does well tell you how the acceleration changes when the obect is moving. When the object is moving, its distance changes and this law tell you what will be this gravity anywhere (this is what is called a field: how much everywhere).

I you dont' want to deal with calculus (not yet), you can try to do it numerically. You can try that with paper and pencil, but with a computer it will be even funnier. However, to be honest the 3-dimensional problem (actually 2D) will be rather demanding: you will have to deal with the 3(2) coordinates. You could restrict the problem to a vertical motion as a first step, specially if you are doing such things for the first time. There will be a lot to discover already, physically, mathematically and computationally.

Try for example to calculate the free fall of an object from an altitude of 63000 km (10 earth radius). For more fun, pretend the object can go through the earth without any friction.
(how would you guess the gravity varies when the onject is 'inside' the earth)

If you want some non-numerical step, you can also study the energy-conservation in this problem. This will tell you the velocity of the object, not as a function of time, but as a function of the position it will reach. That's already something. From the velocity you can calculate the position at any time, by calculus, or numerically.

have fun

Register to reply

Related Discussions
Change of acceleration Introductory Physics Homework 21
Centripetal acceleration, incorporating a change in acceleration around the circle... Introductory Physics Homework 3
Acceleration change in freefall Introductory Physics Homework 18
Weight in N with change in acceleration Advanced Physics Homework 2
Change in a change in acceleration General Physics 4