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#1
Jul1406, 06:01 AM

P: 80

i know those type of question are posted every day but it is short:
one twin is on a spaceship and the other on a planet, moving with relative speed. each twin sees the other's time slow down until the simmetry is not broken, and the moving twin get discovered. but doesn't it mean that in every simmetrical sistem there is always a privileged frame, also if we cannot know it without acceleration? isn't this against the relativity principle? 


#2
Jul1406, 09:24 AM

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You seem to be missing the essential symmetry of the problem.
Either twin can visit the other. If the earthbound twin is Alice and her brother is Baker, Alice can leave the Earth on a spaceship to visit her brother, or her brother can turn around to revisit the Earth. The deltav requirement will be the same in either case. Assuming that Alice and Baker were originally the same age when Baker left Earth, If Alice is the one who travels, she will be the younger twin at their reuniion, she will be the younger twin. If Baker turns around, the reverse will be true. There is no essential assymetry in the problem, nor is there a preferred frame. 


#3
Jul1406, 09:57 AM

P: 80

so, if the guy on the spaceship says that his brother is becoming younger, he is not right: because he is the one that is moving, even if he doesn't know it, so his telescope view is the wrong frame, in fact he will realize later it with an acceleration. in know i'm completly wrong, but for me this seems ok... 


#4
Jul1406, 10:23 AM

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This is an improvement, but it's better to take the "wait and see" approach.
The "wait and see" approach says that simultaneity of distant events is a relative concept, not an absolute one. Therfore one just waits until he/she gets here to see who is older and who is younger. At zero distance, there is no uncertainity about simultaneity  at a distance of 'n' light years, the uncertainity is +/ n years. Another way of saying this: suppose we have to events, A and B. We wish to determine which came first. Basically, if a light beam can reach from event A to event B, everyone will agree that event B is later than event A. If a light beam cannot reach from A to B different observers will have different opinions on which came first. 


#5
Jul1406, 11:04 AM

P: 306

I think born2perform, like me, is asking "help me to understand this" type questions.
I think he is asking "you and me are at rest and have synchronized watches". I start moving and we compare watches while I keep moving. My watch is running slower than yours. I can see that with my own eyes. Therefore I ABSOLUTELY MUST be moving. And you ABSOLUTELY MUST be at rest. 


#6
Jul1406, 11:15 AM

P: 80

and 2 distant watches could be sinchronized, in fact if i put a lamp in the center, and 2 rays start at the same time from the lamp, when they reach the clocks the clocks will start, so they can be synchronized. really i cannot solve this...what i'm thinking of this problem is like: "the truth exists but we cannot know it" i'm just sayng that one frame is true and the other modified.. 


#7
Jul1406, 01:01 PM

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When I say "really" I am making a philosphical statement, which I will make more precise  you can't compare your watch with a distant watch in a manner that is indepedent of the observer. So when I say "really" I actually mean "in an observer independent manner". To use the famous example from Einstein http://www.bartleby.com/173/9.html two events (lightning strokes) which are simultaneous in one frame of reference are NOT simultaneous in another moving frame of reference. 


#8
Jul1406, 01:16 PM

P: 2,043

The problem usually is that two different things are intermixed. Relativistic measurements When objects X and Y change their distance at a constant rate they both will observe that the clocks of their counterparts will run slower, not just clocks, the length (in the direction of travel) will be shorter and their (relativistic) masses will be greater. In actuality none of those properties change, their simply appear to be changed due to relativistic effects. So in other words in relativity clocks never run slower, they only appear to run slower! Paths in spacetime How much time something takes to travel from A to B depends on how we travel in spacetime. If we travel on a geodesic which is the shortest path in spacetime the elapsed time will be maximized. However other paths will take less time. Note that it is not about time running slower or faster but simply on how much time is spent. Think about a trip from A to B comparing a short way and a long way with the same speed. The amount of time you will have traveled is obviously greater for the longer path. Would you, if you compare the odometers, conclude that time slowed down for the shorter path? No you would not right? It is simply that you spent less time. Now with time in spacetime it is exactly the opposite! A longer path will have less time spent than a shorter path. That is counterintuitive for our sublight experiences but if you consider the Minkowski (you can use another form as well where the sign is different but it really does not matter) metric: [tex]ds^2=c^2dt^2  dx^2  dy^2  dz^2[/tex] you see that to calculate the distance between two events is different than in our classical idea of space. If we simplify this metric (only one spatial dimension (s) and make c=1) for the sake of explanation we would get: [tex]ds^2=t^2  ds^2[/tex] Now for two observers who separate and meet later we would have a similar distance in spacetime. So it becomes like a playing match between time and space. If one travels a lot of space (s) it would mean there less amount for time (t) and if one travels no space (s) it would mean that time is maximum. So, I hope you can see that if you compare clocks of different objects with the same distance in spacetime they do not necessarily have to show the same elampsed time, it really depends on how much space they travelled. It will turn out that some travelers simply spent less time than others. So with regard to the twin problem: When forces, such as the electromagnetic force of a rocket engine (the burning of kerosene) cause an object to accelerate it is no longer traveling on a geodesic. And thus the elapsed time will definitely be shorter than if it had traveled on a geodesic. So when A accelerates away from B it means that A is no longer traveling on a geodesic (if both were already not traveling on a geodesic it would also work) and if they would later meet and compare their clocks, it would turn out that less time has elapsed for the traveler. Not, and this is important, because his clock went slower, it did not, but simply because he spent less time traveling through spacetime. 


#9
Jul1606, 12:04 PM

P: 1,473

Einstein's assertion that: "Moving clocks run slow." is somewhat misleading (at least w/o further explanation). What should be said is that: "If one of two synchronized clocks is put in motion, the one put in motion will accumulate less time during the spacetime interval. The spacetime interval is invariant, and it is this principle that resolves the apparent paradox of the twins and other questions re relativity 


#10
Jul1606, 01:31 PM

P: 2,043

The whole "clocks running slow" idea is a constant source of confusion. It implies the idea of absolute time. 


#11
Jul1606, 01:45 PM

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#12
Jul1606, 01:48 PM

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#13
Jul1706, 02:36 AM

P: 1,473

If you don't believe this, ask a high speed pion. 


#14
Jul1706, 05:18 AM

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#15
Jul1706, 07:22 AM

P: 80

Just one more issue:
Going back on twins: One twin leaves the Earth accelerating, and the other stays on the planet. so we know who is moving. Then the twin on the spaceship, that is moving but is not accelerating more, dies, and his son takes control of the spaceship. SO, we know the spaceship is moving, but the son doesn't: for him the system is symmetrical, and he has not a way to discover the truth, that his ship is moving. What you say? 


#16
Jul1706, 09:00 AM

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If, say, one twin accelerates, leaving the other sitting in a "nonmoving" spaceship (nonmoving relative to the frame in which both were originally stationary not accelerating), then, eventually, stops accelerating, each of the twins would see the other moving relative to himself and, therefore, each would see the other's clock moving slower than his. That's not a paradox. The only way there could be a paradox would be to have the two twins come back together again. That would require one of the twins to accelerate again so they can come back together. That could be done in either of two ways: the twin who first accelerated could "decellerate" until he was going back to the "stationary" twin and then "accelerate" to a stop (relative to his twin) or the originally "stationary" twin could accelerate to catch up with the other and then decelerate to a stop (relative to his twin). In the first case, a detailed calculation, including the accelerations, would show that the "accelerating" twin would be younger than the other. In the second case, the same calculation would determine that their clocks would read the same after all the accelerations and decellerations. If the situation involves one spaceship that continues accelerating, it would be easy for the son of the twin on the nonaccelerating spaceship to determine that the other is accelerating and so his clock would continue slowing relative to the other person's. A person on the accelerating spaceship could take himself to be stationary (in his own frame of reference) but would have to accept a "gravitational" force equal to ma which would still cause his clock to slow. 


#17
Jul1906, 07:09 PM

P: 1,473

After the Father croaks, the Son has no information re the history  so its correct to say that as far the Son and the Brother of the father, both view the other as moving  if each sets up a two clock experiment in their own frame to measure the rate of a clock in the other frame, each well conclude that the clock in the other frame runs slow. But this is a different problem and its endemic of all twin type paradox(s). The traveling twin is moving to a new point in spacetime  he will experience a temporal distance ct' and a spatial distance (vt)  the twin that stayed at home only experiences a temporal distance (ct) from start to finish. This is true whether the traveler stops somewhere along the way or turns around and returns  all the clocks in the frame of the stayathome twin read the same. The watch carried by the traveling twin will actually read less whenever the traveling twin stops and his watch is compared with any clock in the original frame  no matter where it is located. This is the surprising result Einstein derived  what is hard to accept is that the final physical difference in the clock readings (an actual time difference) was arrived at by Einstein using mathematics that followed from the observing of times and distances in other frames. The fact that Einstein arrived at physical time difference in a situation involving two inertial observer, neither having a preferred frame  is amazing  Einstein called it a peculiar result.



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