How do I calculate the volume of a spherical slice using integration?

  • Thread starter Thread starter tandoorichicken
  • Start date Start date
  • Tags Tags
    Spherical Volume
Click For Summary

Homework Help Overview

The discussion revolves around calculating the volume of a spherical slice using integration. Participants are exploring the definitions and methods related to the geometry of spherical slices, particularly in relation to integration techniques.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to clarify the definition of a spherical slice, with varying interpretations of how it is formed. Some suggest it involves cutting through two lines of latitude, while others consider the geometry of wedges formed by arcs. Integration methods for calculating volume are also discussed.

Discussion Status

The discussion is active, with participants providing insights into the geometry of spherical slices and suggesting integration as a method for volume calculation. There is a recognition of different interpretations of what constitutes a spherical slice, leading to a productive exploration of the topic.

Contextual Notes

Participants are working under the assumption that the sphere is centered at the origin and have specified the need to integrate between two defined z-values for the slices. The definitions and assumptions about the geometry of the slices are still being clarified.

tandoorichicken
Messages
245
Reaction score
0
How do I find the volume of any spherical slice?
 
Physics news on Phys.org
What exactly do you mean by a spherical slice? My guess would be to take two half great-circles (from pole to pole) and "cut" to the line through center and both poles- although I would call that a "wedge".

If that's what you mean, then the volume depends only on the angle between the two arcs. The volume of the entire sphere is [tex]\frac{4}{3}\pi R^3[/tex]. The volume of a wedge with angle θ between the two arcs is that times [tex]\frac{\theta}{2\pi}= \frac{2}{3}R^3\theta[/tex].
 
a slice:
say you have a circle. then you cut straight through the circle once, and then make another parallel slice. That's what I mean by a spherical slice. Basically you end up with a frying pan like solid.
 
Ah. Instead of slicing through two lines of longitude, you slice along two lines of latitude. (Apparently we slice our apples differently!)

You will have to integrate to get that. Assume the sphere is centerd at (0,0,0) and has radius R. Take the two slices to be at z= z0 and z= z1. For each value of z between those, a cross section will be a circle centered at (0,0,z). The radius of that circle is r= √(R2- z2) and so the circle has area π(R2- z2). Taking the thickness of a thin slice to be dz, the integral becomes
π integral from z0 to z1 of (R2- z2) dz. Hmm, that's easier than I thought it would be.
 

Similar threads

Replies
4
Views
2K
Replies
6
Views
2K
Replies
6
Views
1K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 27 ·
Replies
27
Views
5K
Replies
5
Views
2K
Replies
12
Views
3K