
#1
Jan2604, 09:57 PM

P: 22

I think the reason that my problems have arisen is because of my equation for the force of friction. I have
Ff= ucosAngle That right? 



#2
Jan2604, 10:09 PM

Emeritus
Sci Advisor
PF Gold
P: 10,424

The force due to friction:
[tex]F = \mu N = \mu m g[/tex] Where [itex]\mu[/itex] is the coefficient of friction (either static of kinetic), and [itex]N[/itex] is the normal force. On a horizontal plane, the normal force is just the weight of the object, which is [itex]mg[/itex].  Warren 



#3
Jan2904, 09:38 AM

P: 115

And to include the angle;
[tex] F_f=\mu mg cos \alpha [/tex] 



#4
Jan2904, 11:33 AM

P: 661

Force of Friction Equation?
It is the limiting force of friction or say max friction force exerted and f force due to friction depends on the circumstance
For eg moving on a plane surface Chroots Ans is correct and in case if body is on inclined surface Kishtiks Ans is correct 



#5
Jan3004, 03:10 AM

P: 115





#6
Jan3004, 08:52 AM

P: 640




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