
#1
Oct1006, 05:01 PM

P: 6

Is it true that any smooth manifold admits a complete riemannian metric? Can you prove it? If not can you give a counter example? Obviously we can always put a riemannian metric on any smmoth manifold the question is does the differentable structure allow us to find a complete one.




#2
Oct1206, 03:07 AM

P: 2,955

Best wishes Pete 


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