Calculate the normal force and the tension in the string

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Homework Help Overview

The discussion revolves around calculating the normal force and tension in a string for an object on a frictionless inclined plane at a 60-degree angle. The original poster expresses confusion regarding the relationship between gravitational force, normal force, and tension.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to analyze the forces acting on the object by breaking them into components but struggles to reach a conclusion. Some participants question the validity of the textbook answers and the assumptions made about the forces involved.

Discussion Status

The conversation has highlighted discrepancies between the original poster's calculations and the textbook answers. Participants are exploring the implications of the string's orientation and the gravitational force, with some suggesting that the textbook may contain errors. The original poster plans to seek clarification from their teacher.

Contextual Notes

There is uncertainty regarding the accuracy of the textbook answers, which claim both the normal force and tension are 508 Newtons, while participants suggest that these values should be less than the weight of the object, which is 490 Newtons. The lack of additional information, such as the height of the object or the point of attachment of the string, is noted as a constraint in resolving the problem.

hadoken22
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Hello. I am starting tension in my physics class and am stuck on a problem. I was wondering if anyone could help me out. It seems really simple: an object of mass 50kg is being held by a string attached to the top of a frictionless inclined plane that is 60 degrees above the horizontal. I need to calculate the normal force and the tension in the string.
I am really not sure how to solve this problem. My thinking was that the normal force exerted by the inclined plane would be equal in magnitude to the force of gravity, but opposite in direction. Fg=50kg*9.81*sin(60)=-Fn But, I am not sure that this is really true. It could be that the force of gravity is equal to the sum of the tension and the normal force. I tried breaking the forces down to their components and summing them up, but I did not get very far. I feel that I am failing to grasp some fundamental concepts. Any help would be greatly appreciated. Also, the answer is supposed to be 508 Newtons.
Thank you!
 
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I tried breaking the forces down to their components and summing them up, but I did not get very far
Well, that is the way to solve this problem, so why did you not get very far? How did you go about doing this?

Also, what answer is supposed to be 508 N? Are you sure about that? You said you are to calculate the tension and the normal force. Neither of those is going to be 508N, assuming the string is parallel to the surface of the inclined plane. Look, the weight of the object is only 490N, so if the string is parallel to the surface, the tension and the normal force must each be less than 490N. (And if the string is not parallel to the surface, we need more info -- such as the height of the object and the point of attachment of the string).
 
Thanks for your help. But, what you said about the answers being less than 508 is exactly what I was thinking. Unfortunately the answers in the back of my textbook lists that both values are 508 Newtons. I checked several times that these answers were indeed referring to the correct problem and chapter, and they are. In addition, the string is parallel to the inclined plane and no height is given for the object or the plane. Perhaps the answer in the back is wrong. I found the right answer for all of the other problems that I tried. I'll just have to ask my teacher about this one.

Thanks again.
 
My teacher announced today that the answers in the back of the book are indeed wrong. The answers that I was getting of 425N and 245N turned out to be correct.
 

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