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#1
Oct1406, 07:19 PM

P: 1

Many people have been arguing for a long time that it doesn't. Of course, they couldn't actually give solid proof for this. They based their theory on the fact that if photons had mass at rest than many laws and theories we know today would be wrong. But the question still remains, if photons have no mass at rest, then why is light sucked into black holes. I mean, if light has no mass at rest, then the concept of gravity doesn't apply to it. Also, where does all the energy and momentum come from. I know about the concept of relative mass, but still, even with this, the energy has to come from a source and in my opinion that source has to be an initial mass.



#2
Oct1406, 08:54 PM

P: 546

It is not known absolutely for sure that photons do not have mass. However, there is an experimental upper limit on what that mass could be; and it's pretty darn small.
Additionally, if photons had mass, there should be a third possible polarization for light, and electrostatic potentials should fall off as [tex]\frac{1}{r} e^{\frac{m_\gamma c r}{\hbar}}[/tex]. To understand the statement that even light can't escape from a black hole, you have to understand a little bit about how general relativity describes gravity. General relativity says that the presence of mass (or energy or momentum or pressure, etc.) actually bends the fabric of space and time. When the path of a particle is affected by gravity it happens, not because the particle is feeling a force, but because the particle is travelling along what is effectively a straight line path on a curved surface. When you think about it this way, it seems natural that even light should be affected. A black hole is simply the case where space and time are so bent that every single straight line path that exists leads to one single place. (Of course, to be exact, we should say that every path that exists inside the event horizon leads to one single place. Outside the event horizon, there are paths that don't lead into the black hole.) 


#3
Oct1406, 09:23 PM

P: 481

photons are said to have no mass, or specifically no rest mass, for two reasons. well really theyre the same one but anyway. firstly because an inertial observer can never catch up with a photon and view it at rest. secondly because mass addition requires something traveling at the speed of light to have infinite mass (as a product of its initial mass) which requires an infite amount of energy to accelerate to c. thus nothing with mass can get to speed c, but because the mass addition is a product value something with zero rest mass can. 


#4
Oct1506, 05:19 AM

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Do Photons Have Mass?
This issue has been discussed to death in several threads in both the Quantum physics forum, and the SR/GR forum. Please do your search there and figure out how gravity is a spacetime curvature, and why light follows the "geodesic" of that spacetime curvature. It has NOTHING to do with light having a mass. Zz. 


#5
Oct1506, 05:04 PM

P: 2,954

There is a possibility that a photon has a finite rest mass. The best of current measurements of the photon's proper mass does not have the precision to detect any photon proper mass. Best wishes Pete 


#6
Oct1506, 08:59 PM

P: 2,043

Suppose we have an object with mass. It will curve spacetime and as a consequence all inertial paths are curved in its neighborhood. So any other object nearby, regardless whether it has mass or not, will be subject to these conditions of spacetime. Consider flat spacetime. Each particle that is inertial for a given time interval shows a straight line segment, and each particle that is not inertial for a given time segment shows a curved line segment. Now an object that has mass influences the curvature of spacetime. Then it follows that near an object of mass anything else that showed a straight line segment before does not longer show a straight line segment and the curved line segments are also different. And by the way not only the spatial dimensions of spacetime are subject to curvature, the time dimension is subject to curvature as well. At low relativistic speeds the time curvature is actually stronger than the spatial curvature. Now with regards to black holes sucking in light, it depends on the direction of the light, most light paths will simply approach and then leave the vicinity of the black hole. But some light paths will encounter such curvature that it will be directed to go to the center of the black hole. 


#7
Oct1606, 05:35 AM

P: 2,954

Pete 


#8
Oct1606, 02:37 PM

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P: 7,634

I've said this once or twice or ten times before, but in GR, gravity is not based on "mass", but on the stressenergy tensor. In fact, mass is only defined in GR under special circumstances, such as asymptotically flat spacetimes, or stationary spacetimes.



#9
Oct1806, 09:46 AM

P: 375

Mass is usually used as a comparative measure. Further, the more mass a space object has the more 'gravitational influence' that space object presents.
In this respect for any other object, be it light or a space ship, their mass is not relevant as we all know things fall at the same speed. So whether light has almost no mass and a spaceship has greater mass, all things fall at the same rate. What does affect the apparent rate of fall over ground distance covered is velocity. If the space ship is travelling faster sideways then it will fall to the ground at a greater distance. Give it enough distance and it will miss the Earth all together and continue falling (also called orbiting). The same with respect would go for light if it has mass. Light travels extremely fast so it should be bent from its path much less than the rocket which is travelling much slower. It is not because light weighs less but simply because it is going faster. Hence why we need stars and galaxies to gain noticeable bending of light as they need to exert greater gravitational influence to overcome the light's speed in sufficient time. But the key difference for light, if it has mass, is frequency. Frequency represents the oscillation of light through a point of space as it passes through. We have already established that it does not matter how much mass the light has so if higher frequencies were say heavier than lower frequencies then this would make no difference to the path of either frequency as their mass is inconsequential. However I mentioned frequency because frequency represents how quickly the crests and troughs of the light pass through a point of space. The faster the light rises and falls (the higher its frequency) through its oscillations should effect the path of the light around a gravitational body. Higher frequency light which is oscillation faster should bend less around a gravitational body than should lower frequency light which is oscillating slower. This effect would be similar to the effect found when passing light through triangular prisms. However according to science light is achromatic. This means that the different frequencies are not supposed to bend different degrees around large graviational bodies. 


#10
Oct1806, 12:19 PM

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P: 7,634

Just as light and heavy objects fall at the same rate, different frequencies of light are not chromatically aberrated. They both essentially follow geodesics. Like the case of light and heavy objects falling, this argument iignores the back reaction effects. The clearest argument is this. If you drop a light and heavy argument, the Earth "may move" (note that it won't move as a point mass!). However, the light and heavy object will both arrive at the same point at the same time. It's just that the Earth will move, and stretch by a totally insignificant amount. Similarly, if you send a high frequency and a low frequency light beam around a black hole, the black hole "may move" by a totally insignifcant amount. But there will be no relative deflection of the high frequency vs the low frequency beam if they are sent at the same time. 


#11
Oct1806, 09:41 PM

P: 138

so sound waves are affected by a curvature in space?



#12
Oct1906, 12:19 AM

P: 76

everything is



#13
Oct1906, 08:20 AM

P: 375

God pervect
Do you actually read anything I write? Nothing I wrote in my post that you quoted disagreed with what you rehashed. I'm sorry that I don't use meaningless scientific words. I really don't know where you get the idea that I argued that heavier objects fall faster than smaller objects. I did deliberately ignore the "back reaction effects" as I didn't think this necessary to help the original poster. I apologise that you felt its absence. These "back reaction effects" are that while one body A falls towards another body B; body B will also fall towards body A; and this affects the combined closure speed. If you have two massive spheres of lesser density then they will fall together at a slower speed than two massive spheres of greater density. Simply because both denser spheres will experience greater acceleration towards each other than will the less dense spheres towards each other. Think before you speak please before telling me that I'm presenting flat earth principles. 


#14
Jun1708, 02:10 AM

P: 20

One related question, which may be less ambiguous, would be "What happens to the mass/gravitational field of a black hole when it sucks up more photons?"
From my casual readings, I have to agree with Pete that the issue is more about what the question really means rather than what the answer is. A photon is a quantum object and terms like "stationary" mass (and "constant" momentum for that matter) are not welldefined. My understanding is that an answer like "The stationary mass of a photon is equal to X" is wrong even if you make X = 0. 


#15
Jun1708, 04:46 AM

P: 2,954

Pete 


#16
Jun1708, 12:59 PM

P: 48

Does a photon have mass? in a word, No.
Light is not a substance; light is electromagnetic energy. a "photon" is a unit of measure of that energy. a photon is no more a particle of light than a phon is a particle of sound. rg 


#17
Jun1708, 04:32 PM

P: 2,954

Best wishes Pete 


#18
Jul1908, 10:43 PM

P: 2

Way back in 10/14/06, FunkyDwarf said:
“photons are said to have no mass, or specifically no rest mass, for two reasons. ...firstly because an inertial observer can never catch up with a photon and view it at rest. secondly because mass addition requires something traveling at the speed of light to have infinite mass (as a product of its initial mass) which requires an infite amount of energy to accelerate to c. thus nothing with mass can get to speed c, but because the mass addition is a product value something with zero rest mass can.” The first point is incorrect. If you could “catch up” to a photon you would still measure its velocity as c, the speed of light, because c is an invariant. You would, however, measure its frequency as 0 due to red shift. The second point is correct but misses the point. The point is that anything that travels at the speed of light can ONLY travel at the speed of light. It can never be “at rest” because it IS light and the speed of light in a vacuum is invariant. Therefore, the “rest mass” of a photon is NOT zero; the photon has no rest mass because it can NOT be “at rest”. I know this is an old thread and my response is to a 2 year old post but the thread, in total, has helped me think through some basic issues in a concise way. The discussion about photons being E&M waves versus being or having energy has nothing to do with “rest mass” and is more metaphysics (or semantics) than physics. Interesting and correct, but not on point. The point is: photons are light, light travels at an invariant speed, c, in a vacuum and cannot be at rest; therefore photons cannot have “rest mass” which does NOT mean the “rest mass” of a photon is zero. Incidentally, it is not a "theory" that the speed of light in vacuum is invariant; it is an axiom. It is the foundation on which both Special and General Relativity are built. 


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