
#1
Feb504, 11:33 AM

P: 23

The transverse displacement of a harmonic wave on a stretched rope is y = 0.03 cos(2.7 t  2.9 x), where x and y are in meters and t is in seconds. A 5 meter length of this rope has a mass of 1.5 kg.
************** a) What is tension in rope? b) At time t = 0, consider a 1/2 wavelength long section of the rope which is carrying the wave y = 0.03 cos(2.7 t  2.9 x) between two points which have zero displacement (y = 0). Find the total force exerted by the rest of the rope on this section. Neglect any effects due to the weight of the rope. Use the smallangle approximation where q, sin(q), and tan(q) are all approximately equal to each other. //////////////////////////////////////// a) Not too bad. Tension= V^2*mu where V is velocity and mu is linear density. V=omega/K, thus, v=.9310 m/s mu=mass/length...so 1.5kg/5m =.2600N Tension equals .2600N, which is correct answer. b) Ok, part b is giving me a headache. I don't know how to start this problem really. I've included a picture to help. 


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