Register to reply

Relativistic Electron Wave

by Mindscrape
Tags: electron, relativistic, wave
Share this thread:
Mindscrape
#1
Oct26-06, 02:55 PM
P: 1,874
The dispersion relation for the free relativisitic electron wave is [tex] \omega (k) = \sqrt{c^2 k^2 + (m_e c^2/ \hbar)^2}[/tex]. Obtain expressions for the phase velocity and group velocity of these waves and show that their product is a constant, independent of k. From your result, what can you conclude about the group velocity if the phase velocity is greater than the speed of light?

The group velocity will be easy to find because I can just differentiate with respect to k. I am not really sure what to do for the phase velocity. I figure that since [tex]v_p = f \lambda = E/p [/tex] then I could use the relativistic energy expression [tex]E = (p^2 c^2 + m^2 c^4)^{\frac{1}{2}}[/tex]. I am unsure about how to tackle the momentum. Does an electron have a de Broglie wave dispersion?
Phys.Org News Partner Science news on Phys.org
Scientists discover RNA modifications in some unexpected places
Scientists discover tropical tree microbiome in Panama
'Squid skin' metamaterials project yields vivid color display
OlderDan
#2
Oct26-06, 03:04 PM
Sci Advisor
HW Helper
P: 3,031
Showing the product to be constant was just done in another thread, but you can do it on your own. Phase velocity is ω/k.


Register to reply

Related Discussions
Why does electron have wave property Quantum Physics 5
Relativistic Electron Introductory Physics Homework 2
Group velocity of relativistic wave packet Advanced Physics Homework 2