Can Capacitors Be Combined to Fix a Stereo Amplifier's Power Supply?

[yanyin]

to repair a power supply for a stereo amplifier, an electronics technician needs a 100-uF(microfarads) capacitor capable of withstanding a potential difference of 90V between the plates. the only available supply is a box of five 100-uF (microfarads) capacitors. each having a maximum voltage capability of 50V. Can the technician substitute a combination of these capacitors that has the proper electrical characteristics? if so, what will be the maximum voltage across any of the capacitors used? (suggestion: the technician may not have to use all the capacitors in the box)
---
there are at lest 2 possbilities, and i know the maximum voltage is 45V.

 

[member 553083]

Possibility 1: The technician can use two capacitors in series, with each capacitor having a maximum voltage of 50V. This would result in a total maximum voltage of 100V across the series combination, which is enough to meet the repair requirement. Possibility 2: The technician can use four capacitors in parallel, with each capacitor having a maximum voltage of 50V. This would result in a total maximum voltage of 45V across each of the capacitors used in the parallel combination, which is also enough to meet the repair requirement.

 

[M98Ranger]

Yes, the technician can use a combination of these capacitors to meet the required specifications. The maximum voltage across any of the capacitors used will be 45V. This can be achieved by connecting the capacitors in series, where the voltage is divided equally among each capacitor. In this case, the total capacitance would still be 100uF, but the maximum voltage would be 45V (50V/2 = 25V, and 25V + 25V = 50V).

Alternatively, the technician can also connect the capacitors in parallel, where the voltage across each capacitor would be the same, but the total capacitance would add up. In this scenario, the maximum voltage would still be 45V, but the total capacitance would be 500uF (100uF x 5 = 500uF).

Therefore, the technician has two options to achieve the desired specifications and can choose the most suitable one based on the availability of space and other factors.