# How fast must you throw a snowball against a wall in order to make it melt?

by twotaileddemon
Tags: melt, order, snowball, throw, wall
 P: 263 Hi, I'm new to this forum and I have a question. In my physics class we are discussing energy and work. We are given this problem: "It is exactly 0*C. How fast must you throw a snowball against a wall in order to make it completely melt? (Assume all the energy is transferred to the snowball and neglect air friction)" Now.. considering there is almost no information given, how am I supposed to solve this? I know potential energy is mgh and kinetc is .5mv^2. Work is Fs, or change in kinetic energy. It's just.. give so little details I don't know where to start. Can anyone tell me how to start the problem, or any general guidance without giving the answer? Thanks :)
 Sci Advisor PF Gold P: 2,085 How much energy do you need to turn ice into water?
 P: 263 I'm not really sure.. we never went over that. Is it just an equation that I'm looking for?
 P: 263 How fast must you throw a snowball against a wall in order to make it melt? I'm pretty sure kinetic energy is used somehow. And this may be completely off, but could you do something with specific heat or melting/boiling points? I'm given no numerical values to work with.. so I'm a bit lost xx;;
 P: 122 http://en.wikipedia.org/wiki/Standar...ange_of_fusion. Set the energy required equal to the kinetic energy.
 P: 263 .5m(Vf-Vo)^2 = Ei+El i = initial l = lost Is this okay?
 P: 122 Yes that's fine. Although I'm not sure what you mean by energy lost, the energy is gained by the snowball and then converted.
 P: 263 So to solve for Vf, I would get sq rt (Ei + El + .5mVo^2)/(.5m) = Vf Is that my answer?
 Sci Advisor PF Gold P: 2,085 You need to find the energy needed to melt the snowball. Use the mass and heat of fusion.
 P: 122 $$Ei = 0.5mV_{i}^2 = 0$$ $$mL = 1/2mV_{f}^2$$, L = latent heat of fusion $$=> V_{f} = sqrt(2L)$$ You can think of m being 1 gram, basically your using a unit mass for L. edit: put 0 instead of f sorry.
 P: 263 I guess I'm so confused is because I've never heard the term latent heat of fusion until now, and it was not discussed in class. So sorry if I seem clueless.. because I am xx;; So the sq rt of mVo^2 would be the correct answer when substituting 1/2mVo^2 for L, ... the 2's cancel out and you're left with sq rt mVo^2? Or do you add the .5mVi^2 to it?
 P: 263 Uh.. oh I see. Vf was already derived. So sqrt of 2L is the answer? There is no other way to simplify it, because my teacher is going to wonder how I came up with that when we didn't discuss it xx;; I'm so sorry for wasting everyone's time too. I appreciate all the help immensely.
 P: 263 Okay so let me just get something straight. L = 1/2mVf^2 Vf = sqrt 2L Where does the mass of the snowball go in the equation? Vf = sqrt 2(1/2mVo^2) = sqrt mVo^2 ?
 P: 122 If you read that page you have a value for L, 334.5 joules per gram. Specific heats and latent heat of fusions are related, see here http://www.rwc.uc.edu/koehler/biophys/8c.html .
 Sci Advisor PF Gold P: 2,085 Max Eilerson, why did you choose Ei=0? Snowball has non-zero kinetic energy before collision, zero final kinetic energy. KEi=(m*v_i^2)/2 This must equal the latent heat of fusion of snowball, which is L=m*334 kJ/kg equate these and solve for v_i. Does that make sense twotaileddemon? Do you need to know the mass? Edit: I had typo in specific latent heat value 334
 P: 263 I did read the page, thanks for it. So Vf is sqrt of 669 J which is about 25.86 J... okay. Thanks :). I will ask my teacher tomorrow whether or not this is allowed since we haven't learned it yet.. maybe he wanted us to do research. Thanks again, I really really appreciate it :)
 P: 122 marcus I got my subscripts confused sorry. The kinetic energy doesn't equal the latent heat of fusion of the snowball it equals mL.
 P: 263 Max Eilerson, why did you choose Ei=0? Snowball has non-zero kinetic energy before collision, zero final kinetic energy. KEi=(m*v_i^2)/2 This must equal the latent heat of fusion of snowball, which is L=m*334 kJ/kg [So do you isolate v_i.. so I get sq rt 334 J / 2kg as my answer? or simplifying it, 117 J / kg? = 117 m/s? equate these and solve for v_i. Does that make sense twotaileddemon? Do you need to know the mass?[No, the velocity it needs to be to melt when it hits a wall]

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