Find Work Done by Engine in One Propeller Rev - 171 hp, 2310 RPM, 527.612 N*m

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Homework Help Overview

The problem involves calculating the work done by an aircraft engine on a propeller during one complete revolution, given the power output and rotational speed of the engine. The subject area includes concepts from mechanics and rotational dynamics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between power, work, and rotational motion, with one participant converting horsepower to watts and questioning the revolutions per second. Another participant suggests using a specific equation related to rotational work.

Discussion Status

The discussion is ongoing, with participants exploring different methods to calculate work done. There is an exchange of ideas regarding the equivalence of approaches, but no consensus has been reached on a specific method.

Contextual Notes

Participants are working within the constraints of the information provided, including the power output in horsepower and the torque value. There is an implicit assumption that the relationship between power, torque, and rotational speed is applicable to the problem.

ACLerok
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The engine of an aircraft propeller delivers an amount of power 171. hp to the propeller at a rotational velocity of 2310 rev/min. I found the torque produced to be 527.612 N*m
How can i find the work done by the engine in one rev of the propeller?
 
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Power is the rate at which work is done.

171 hp = 746 W = 746 J/s

You have how many revs / s ?

(J/s)/(r/s) = J/r
 
use this equation to find the work done: W = τθ (it's the rotational analog to W = Fd; realize that it's still a dot product, but we've simplified already)
 
Touche, gnome.

ACLerok: you should get the same answer either way.
 

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