Is the Sum of Square Roots of 2 and 3 Irrational? A Proof by Contradiction

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SUMMARY

The discussion centers on proving that the sum of the square roots of 2 and 3, specifically 2^(1/2) + 3^(1/2), is irrational. A proof by contradiction is suggested, starting with the assertion that 6^(1/2) is irrational. The proof involves expressing a square root as a fraction a/b, squaring both sides, and analyzing the prime factorization, which shows that if z is rational, it must be a perfect square. Since 6 is not a perfect square, the conclusion is that 2^(1/2) + 3^(1/2) is indeed irrational.

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Yeh just having a problem seeing a way to prove that 6^(1/2) is irrational.

Using this answer and proof by contradiction I need to prove that
2^(1/2) + 3^(1/2)is also irrational, however I sould be able to attempt this if I can get the above right.

Any help much appreciated.
 
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Here's a better proof than contradiction.

let z be the sqrt of any integer, if it is rational write it as a/b, do the usual squaring thing so that

z.b^2= a^2

look at the prime decompostions on both sides. Every prime mus occur with multiplicity two on the rhs, so it does on the lhs, which tells us in the prime decomposition of z every prime occurs twice, that is z is a perfect square. 6 is not a perfect square.
 
Thanks for that, the rest worked out a treat!
 

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