Solving Algebra of Functions: f(500)=3, f(600)?

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Discussion Overview

The discussion revolves around solving a problem related to the algebra of functions, specifically determining the value of f(600) given that f(500) = 3 and the functional equation f(xy) = f(x)/y. The scope includes mathematical reasoning and problem-solving techniques.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant expresses uncertainty about how to approach the problem involving the function f.
  • Another participant provides the functional equation f(xy) = f(x)/y and suggests substituting values to find y when xy = 500 and x = 600.
  • A subsequent post calculates that 600 can be expressed as 500 multiplied by 6/5.
  • A later reply acknowledges the simplicity of the calculation and expresses gratitude.

Areas of Agreement / Disagreement

The discussion does not present any explicit disagreements, but it does not reach a consensus on the value of f(600) based on the provided information.

Contextual Notes

The discussion does not clarify the assumptions regarding the function f or any additional properties it may have, which could affect the determination of f(600).

Moose352
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I'm not too confident with problems dealing with the algebra of functions. For example, how would you approach this problem:

Function f satisfies: f(xy) = f(x)/y
If f(500) = 3, what is f(600)?

Thanks
 
Last edited:
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[tex]f(xy)=\frac{f(x)}{y}[/tex]
Now, if
[tex]xy=500[/tex] and [tex]x=600[/tex]
can you figure out what [tex]y[/tex] is?
 
600=500*(6/5)
 
Ah! Simple enough. Thanks a bunch.
 

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