A Simple Pendulum and Friction problem

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SUMMARY

The discussion centers on calculating the work done by the frictional force on a simple pendulum after one complete period using the equation \(((\beta)^2)'= \frac{2g}{l}(\cos\beta - \cos\theta)\). Here, \(\theta\) represents the maximum angle of motion, while \(l\) is the length of the pendulum string. The user initially sought guidance on integrating the force of friction over the pendulum's path but later resolved the issue independently, indicating the problem was straightforward.

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Ed Quanta
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Im supposed to calculate the work done by the frictional force on a simple pendulum after one period. I have to use the following equation to do this calculation.

((beta)^2)'= (2g/l)(cosbeta - costheta) where thetha is the the maximum angle of the motion.
In other words theta is the angle at which the derivative of beta=0. l is the length of the pendulum string.

How do I use this equation to determine the path taken by the pendulum so I know what I am integrating the force of friction over?

By the way, I am given information regarding the initial position of the ball above the floor, the length of the pendulum wire, and the ceiling height.
 
Last edited:
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Nevermind the help, I figured it out. It was an easy question. Sorry for wasting internet space.
 

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