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Initial Velocity Question

 
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Nov4-06, 06:10 PM   #1
 

Initial Velocity Question


Ok So if I were to launch a waterballoon with a waterballoon launcher VERTICALLY , how could I find out the Initial Velocity With OUT a stop watch? My other supplies include a meter stick
 
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Nov4-06, 06:11 PM   #2
 
Are you familiar with conservation of energy?
 
Nov4-06, 06:13 PM   #3
 
This is for a lab at school and you get Extra Credit if you can figure out the first part without a stop watch. Would i have to weigh it? And sorry, im not familiar with conservation of energy
 
Nov4-06, 06:15 PM   #4
 

Initial Velocity Question


Ok, are you familiar with the equations of motion?
 
Nov4-06, 06:17 PM   #5
 
I am familiar with the equations for angles ( sin, cos), displacement in X,Y , etc,, for constant/non constant velocities and Trajectories
 
Nov4-06, 06:19 PM   #6
 
Look through them and try to find one that involves the parameters you think are going to be important and post it.
 
Nov4-06, 06:19 PM   #7
 
This isnt really a homework question but w/e

Thanks again
 
Nov4-06, 06:22 PM   #8
 
Well if I am shooting an object vertically then Displacment X will be 0m, and
Vy = Vo * sin(90) because the degrees will be 90
VFy = 0 m/s

Thats about all the variables i know atm

Im unsure of which equation to use
 
Nov4-06, 06:25 PM   #9
 
Well, dont solve any equations yet, just look for some that might be useful, and well work from there.
 
Nov4-06, 06:27 PM   #10
 
Would this work
VFy^2 = VOy^2 + 2a*Displacment Y
 
Nov4-06, 06:28 PM   #11
 
Aha, you are on to something. Keep going.
 
Nov4-06, 06:30 PM   #12
 
Displacment Y = {(Vo^2+sin(2*angle)} / g

Only other one i know that doesnt involve time
 
Nov4-06, 06:33 PM   #13
 
where did this come from? You were on the right track before. Maybe you should take a closer look at your first equation.
 
Nov4-06, 06:35 PM   #14
 
its equation for X or Y displacment
I am looking for Initial Velocity (Vo) and those two are the only ones that do not include time because i wont have a stop watch when doing this experiment
 
Nov4-06, 06:37 PM   #15
 
Yes, look at your first equation, and you tell me what each of those terms mean.
 
Nov4-06, 06:39 PM   #16
 
VFy^2 = VOy^2 + 2a*Displacment Y
I am looking for Initial Velocity and not just VOy
Final Velocity of Y = is 0 m/s in this case
VOy^2 = is unknown
a = 9.81m/s^2 in this case
Displacment Y = is also unknown
 
Nov4-06, 06:41 PM   #17
 
Ok, we need to get this terminology straight.

[tex]V_{fy}[/tex] means the final velocity in the y direction.

[tex] V_{oy} [/tex] means the initial velocity in the y direction.

Does this help at all?

Final Velocity of Y = is 0 m/s in this case
Yes, that's correct. Now when does this occur?
 
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