
#1
Nov406, 06:10 PM

P: 36

Ok So if I were to launch a waterballoon with a waterballoon launcher VERTICALLY , how could I find out the Initial Velocity With OUT a stop watch? My other supplies include a meter stick




#3
Nov406, 06:13 PM

P: 36

This is for a lab at school and you get Extra Credit if you can figure out the first part without a stop watch. Would i have to weigh it? And sorry, im not familiar with conservation of energy




#4
Nov406, 06:15 PM

P: 4,780

Initial Velocity Question
Ok, are you familiar with the equations of motion?




#5
Nov406, 06:17 PM

P: 36

I am familiar with the equations for angles ( sin, cos), displacement in X,Y , etc,, for constant/non constant velocities and Trajectories




#6
Nov406, 06:19 PM

P: 4,780

Look through them and try to find one that involves the parameters you think are going to be important and post it.




#7
Nov406, 06:19 PM

P: 36

This isnt really a homework question but w/e
Thanks again 



#8
Nov406, 06:22 PM

P: 36

Well if I am shooting an object vertically then Displacment X will be 0m, and
Vy = Vo * sin(90) because the degrees will be 90 VFy = 0 m/s Thats about all the variables i know atm Im unsure of which equation to use 



#9
Nov406, 06:25 PM

P: 4,780

Well, dont solve any equations yet, just look for some that might be useful, and well work from there.




#10
Nov406, 06:27 PM

P: 36

Would this work
VFy^2 = VOy^2 + 2a*Displacment Y 



#12
Nov406, 06:30 PM

P: 36

Displacment Y = {(Vo^2+sin(2*angle)} / g
Only other one i know that doesnt involve time 



#13
Nov406, 06:33 PM

P: 4,780

where did this come from? You were on the right track before. Maybe you should take a closer look at your first equation.




#14
Nov406, 06:35 PM

P: 36

its equation for X or Y displacment
I am looking for Initial Velocity (Vo) and those two are the only ones that do not include time because i wont have a stop watch when doing this experiment 



#15
Nov406, 06:37 PM

P: 4,780

Yes, look at your first equation, and you tell me what each of those terms mean.




#16
Nov406, 06:39 PM

P: 36

VFy^2 = VOy^2 + 2a*Displacment Y
I am looking for Initial Velocity and not just VOy Final Velocity of Y = is 0 m/s in this case VOy^2 = is unknown a = 9.81m/s^2 in this case Displacment Y = is also unknown 



#17
Nov406, 06:41 PM

P: 4,780

Ok, we need to get this terminology straight.
[tex]V_{fy}[/tex] means the final velocity in the y direction. [tex] V_{oy} [/tex] means the initial velocity in the y direction. Does this help at all? 



#18
Nov406, 06:44 PM

P: 36

VFy That occurs when the object stops right before it comes back down
I Know what the terminology means, 


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