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Initial Velocity Question |
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| Nov4-06, 06:10 PM | #1 |
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Initial Velocity Question
Ok So if I were to launch a waterballoon with a waterballoon launcher VERTICALLY , how could I find out the Initial Velocity With OUT a stop watch? My other supplies include a meter stick
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| Nov4-06, 06:11 PM | #2 |
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Are you familiar with conservation of energy?
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| Nov4-06, 06:13 PM | #3 |
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This is for a lab at school and you get Extra Credit if you can figure out the first part without a stop watch. Would i have to weigh it? And sorry, im not familiar with conservation of energy
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| Nov4-06, 06:15 PM | #4 |
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Initial Velocity Question
Ok, are you familiar with the equations of motion?
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| Nov4-06, 06:17 PM | #5 |
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I am familiar with the equations for angles ( sin, cos), displacement in X,Y , etc,, for constant/non constant velocities and Trajectories
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| Nov4-06, 06:19 PM | #6 |
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Look through them and try to find one that involves the parameters you think are going to be important and post it.
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| Nov4-06, 06:19 PM | #7 |
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This isnt really a homework question but w/e
Thanks again |
| Nov4-06, 06:22 PM | #8 |
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Well if I am shooting an object vertically then Displacment X will be 0m, and
Vy = Vo * sin(90) because the degrees will be 90 VFy = 0 m/s Thats about all the variables i know atm Im unsure of which equation to use |
| Nov4-06, 06:25 PM | #9 |
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Well, dont solve any equations yet, just look for some that might be useful, and well work from there.
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| Nov4-06, 06:27 PM | #10 |
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Would this work
VFy^2 = VOy^2 + 2a*Displacment Y |
| Nov4-06, 06:28 PM | #11 |
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Aha, you are on to something. Keep going.
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| Nov4-06, 06:30 PM | #12 |
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Displacment Y = {(Vo^2+sin(2*angle)} / g
Only other one i know that doesnt involve time |
| Nov4-06, 06:33 PM | #13 |
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where did this come from? You were on the right track before. Maybe you should take a closer look at your first equation.
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| Nov4-06, 06:35 PM | #14 |
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its equation for X or Y displacment
I am looking for Initial Velocity (Vo) and those two are the only ones that do not include time because i wont have a stop watch when doing this experiment |
| Nov4-06, 06:37 PM | #15 |
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Yes, look at your first equation, and you tell me what each of those terms mean.
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| Nov4-06, 06:39 PM | #16 |
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VFy^2 = VOy^2 + 2a*Displacment Y
I am looking for Initial Velocity and not just VOy Final Velocity of Y = is 0 m/s in this case VOy^2 = is unknown a = 9.81m/s^2 in this case Displacment Y = is also unknown |
| Nov4-06, 06:41 PM | #17 |
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Ok, we need to get this terminology straight.
[tex]V_{fy}[/tex] means the final velocity in the y direction. [tex] V_{oy} [/tex] means the initial velocity in the y direction. Does this help at all? |
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