Projectile Motion: initial velocity problem

In summary, to determine the initial velocity of a projectile that returns to its launch level after 10.0 seconds and travels 300.0m horizontally, you can use the equation Δx=v0xt and Δy=v0yt+1/2gt^2. Solving for the horizontal velocity (v0x), you can find that it is 30m/s. To find the initial vertical velocity (v0y), you can use the equation v0y=vfy-gt, where vf is the final velocity at the top of the flight and t is the time it takes to reach the top. This will allow you to fully determine the initial velocity of the projectile.
  • #1
msun5040
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0

Homework Statement


Determine the initial velocity of a projectile that reuturns to launch level 10.0 seconds after it is launched and lands 300.0m away from the launch site.

Homework Equations


Δx=v0xt
Δy=v0yt+1/2gt2

The Attempt at a Solution


[/B] 300=v0x(10)
v0x=30m/s
I don't know how to procees with this problem since it appears that I'm missing v0y. I have time and the initial x component for velocity, but I don't know how I would use that to find the initial y component of velocity.
 
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  • #2
The projectile (rather obviously) must take the same time to travel 300m horizontally as it does to travel vertically up and down.

So you know the time it takes to get to the top of the flight. You also know the acceleration and the final velocity at the top. Find an equation that gives you the initial vertical velocity.
 

1. What is projectile motion?

Projectile motion is the motion of an object through the air or space under the influence of gravity. It follows a curved path called a parabola, and is influenced by the initial velocity and angle of launch.

2. How can I calculate the initial velocity in a projectile motion problem?

The initial velocity in a projectile motion problem can be calculated using the equation V0 = V0x + V0y, where V0 is the initial velocity, V0x is the initial velocity in the x-direction, and V0y is the initial velocity in the y-direction.

3. What is the range of a projectile?

The range of a projectile is the horizontal distance it travels before hitting the ground. It can be calculated using the equation R = (V02sin2θ)/g, where R is the range, V0 is the initial velocity, θ is the angle of launch, and g is the acceleration due to gravity.

4. How does air resistance affect projectile motion?

Air resistance, also known as drag, can affect the trajectory and velocity of a projectile by slowing it down. This is because air resistance acts in the opposite direction of the projectile's motion. In some cases, air resistance may also cause the projectile to follow a non-parabolic path.

5. Can you explain the concept of maximum height in projectile motion?

The maximum height in projectile motion is the highest point reached by the projectile during its motion. It can be calculated using the equation H = (V02sin2θ)/2g, where H is the maximum height, V0 is the initial velocity, θ is the angle of launch, and g is the acceleration due to gravity. The maximum height occurs when the vertical component of the initial velocity is zero.

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