Constant force exerted on the ball by the wall?

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SUMMARY

The discussion centers on calculating the constant force exerted on a 2.5 kg ball that strikes a wall at 8.5 m/s and rebounds at 7.5 m/s, with contact lasting 0.25 seconds. The momentum before the collision is -21.25 kg·m/s, while the momentum after is 18.75 kg·m/s. The change in momentum is 40 kg·m/s, leading to an average force of 160 N exerted by the wall on the ball, calculated using the formula for force as the rate of change of momentum.

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a 2.5 kg ball strikes a wall with a velocity of 8.5 m/s to the left. The ball bounces off with a velocity of 7.5 m/s to the right. If the ball is in contact with the wall for .25s, what is the constant force exerted on the ball by the wall?
 
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Momentum to the left, before the collision, is (- 8.5m/s)(2.5 kg) (negative because it is to the left). Momentum to the right, after the collision is (7.5 m/s)(2.5kg). Change in momentum is the difference between those: (7.5 m/s)(2.5kg)+(8.5m/s)(2.5 kg).
Since that took place in 0.25 s, the average rate of change of momentum is that divided by 0.25 s. Force IS rate of change of momentum.
 

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